0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is p when 12p plus 4q 55?
If 12p + 4q = 55, then p = (55 - 4q)/12
What is 3-4q equals 10q plus 10?
3 -4q = 10q + 10 3 - 10 = 10q + 4q -7 = 14q q = -1/2
How do you solve r equals 4q-5p over 9 solve for p?
Do you mean: r = (4q-5p)/9? If so then: p = (9r-4q)/-5
What is 4Q in FG?
Four quarters in a football game
The value in cents of q quarters?
i think its 4q
What is p when 12p plus 4q 55?
If 12p + 4q = 55, then p = (55 - 4q)/12
What is 4q plus 1 equals 15?
4q + 1 = 15 4q = 16 q = 4
What is 3-4q equals 10q plus 10?
3 -4q = 10q + 10 3 - 10 = 10q + 4q -7 = 14q q = -1/2
What is -6q plus 7-2 plus 4q?
The given expression when simplified is: 5 -2q
How do you solve 6q-2060 plus 4q?
It is: 10q-2060 when simplified.
What is 12q - 4q?
12q - 4q = 8
What is 3p plus 4q if p is 5 and q is -2?
(3*5)+(4*-2) = 7
How do yousimplify 26p plus q plus r plus 4q plus 5r?
You'd have no problem at all if it was [ 26 pigs + 1 quart + 1 rat + 4 quarts + 5 rats ]. You'd add up the quarts, and then you'd add up the rats. You do the same with p's, q's, and r's . 26p + q + r + 4q + 5r = 26p + 5q + 6r
How do you solve r equals 4q-5p over 9 solve for p?
Do you mean: r = (4q-5p)/9? If so then: p = (9r-4q)/-5
How do you work out -6q 7-2 4q?
If you mean: -6q+7-2+4q then it is 5-2q when simplified
If the ratio of the roots of the equation x2 plus px plus q0 is equal to the ratio of the roots of x62 plus lx plus m0 prove that mp2ql2.?
Thanks, Ankur. Let x^2+px+q=0 be Eqn 1 (I have shortened q0 to q) Let x^2+lx+m=0 be Eqn 2 I use the ^ to mean raised to the power of i.e. p^2 means p squared I use * to mean multiply The two roots of Eqn 1 (using the quadratic formula) are x =[-p±sqrt(p^2-4q)]/2 or separately [-p+sqrt(p^2-4q)]/2 and [-p-sqrt(p^2-4q)]/2 The two roots of Eqn 2 are x =[-l±sqrt(l^2-4m)]/2 or separately [-l+sqrt(l^2-4m)]/2 and [-l-sqrt(l^2-4m)]/2 Now we are told that the ratio of the roots of the two equations are equal. So {[-p+sqrt(p^2-4q)]/2} / {[-p-sqrt(p^2-4q)]/2} = {[-l+sqrt(l^2-4m)]/2} / {[-l-sqrt(l^2-4m)]/2} Cancel out the denominator 2 and cross multiply and ==>[-p+sqrt(p^2-4q)] * [ -l-sqrt(l^2-4m)] = [-p-sqrt(p^2-4q)] * [-l+sqrt(l^2-4m)] Simplify by multiplying each side ==>lp + p*sqrt(l^2-4m) - l*sqrt(p^2-4q) + [sqrt(p^2-4q)]*(l^2-4m)] = lp - p*sqrt(l^2-4m) + l*sqrt(p^2-4q) + [sqrt(p^2-4q)]*(l^2-4m)] Now cancel out lp as it's on both side and cancel out [sqrt(p^2-4q)]*(l^2-4m) because that's on both sides. Simplify by bring like terms together and ==>2p*sqrt(l^2-4m) = 2l*sqrt(p^2-4q) Cancel out the 2 on each side and square each side. ==>p^2(l^2-4m) = l^2(p^2-4q) Simply by multiplying out ==>p^2*l^2 - 4m*p^2 = p^2l^2 - l^2*4q Cancel out p^2*l^2 ==>-4m*p^2 = -4q l^2 Cancel out the -4 and voila ++> mp^2 = ql^2 If there is a shorter solution, I'd love to see it.
What is 4Q?
It's slang for "F&*k you."
