You'd have no problem at all if it was [ 26 pigs + 1 quart + 1 rat + 4 quarts + 5 rats ].
You'd add up the quarts, and then you'd add up the rats.
You do the same with p's, q's, and r's .
26p + q + r + 4q + 5r = 26p + 5q + 6r
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It is a string of algebraic terms.
5r + r = 6r
If: 2p+5r = q Then: p = (q-5r)/2
1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!
First, translate it into an algebraic equation:4 + 5r = -11Then we subtract 4 from both sides:4 + 5r - 4 = -11 - 4Now we can simplify our numbers together:(4 - 4) + 5r = -11 - 40 + 5r = -155r = -15Now we divide both sides by 5:(5r / 5) = (-15 / 5)r = -3