It is a string of algebraic terms.
5r + r = 6r
If: 2p+5r = q Then: p = (q-5r)/2
1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!
First, translate it into an algebraic equation:4 + 5r = -11Then we subtract 4 from both sides:4 + 5r - 4 = -11 - 4Now we can simplify our numbers together:(4 - 4) + 5r = -11 - 40 + 5r = -155r = -15Now we divide both sides by 5:(5r / 5) = (-15 / 5)r = -3
It is a string of algebraic terms.
5r + r = 6r
-5r + 8r + 5 = 3r +5
r+5r+5=-25
9(9p + 5r)(9p + 5r)
I hope you mean "What is the solution for the problem 5R plus 6 equals 36". In that case 5R + 6 = 36 5R = 36 - 6 5R = 30 R = 6
If: 2p+5r = q Then: p = (q-5r)/2
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
(5r - 4)(5r + 4)
Combine the ' 9r ' and the ' -5r ' . Replace them with ' 4r '.
You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6
5r + 8 = -12Subtract 8 from each side:5r = -20Divide each side by 5:r = -4