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A square of side 22 has an area of 484. Rectangle 23 x 21 has an area of 483...

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Q: What is the maximum area for a rectangle with a perimeter that is 88?
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If Perimeter of a rectangle that has a width of x inches and a length of x plus 16 inches is 2x plus 2x plus 16 inches simplify the expression for the perimeter Find the perimeter if x equals 14?

If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.


A regular octagon with sides of length 11 and an apothem of length 8.85 has an area of what?

An apothem of a regular polygon is a segment from its center to the midpoint of a side. You can use the apothem to find the area of a regular polygon using this formula: A = pa/2 where p is the perimeter of the figure and a is the apothem. For a regular octagon with side length 11, the perimeter p = 8(11) = 88. So the area would be A = 88(8.85)/2 = 389.4 square units.


If the perimeter of a quadrilateral is 88 inches find the length of each side when side one is X plus 5?

Which quadrilateral? What is x?


What is Length and width of a rectangular lot with a perimeter of 88 meters if the length is 4 meters more than the width?

The perimeter is L(length) x 2 + W(width) x 2 So 2L + 2W = 88 And L = W+4 So we can now replace the L in the equation and we get 2(W+4) + 2W = 88 Work out the brackets and we get 2W + 8 + 2 W = 88 Subtract 8 from both sides, and we get 2W + 2W = 80 or, 4W = 80 so we can divide both sides by 4 and we get W = 20 So now we can add 4 to the width and we get the length as 24. Now, to check the calculation, we add them all up Length 1 = 24 Length 2 = 24 Width 1 ==20 Width 2 ==20 Perimeter - 88


Why does The perimeter of a rectangular park is 218 yards The park is 44 yards wide What is the length of the park?

Let the length be x: 2(x+44) = 218 yards 2x+88 =218 2x = 218-88 2x = 130 x = 65 yards Check: 65+65+44+44 = 218 yards

Related questions

If The area of a rectangle is 176 sq cm what is the perimeter?

You can't tell the perimeter from knowing the area.There are an infinite number of rectangles with different dimensions that all have the same area.Here are a few examples.1 x 176 . . . perimeter = 3542 x 88 . . . perimeter = 1804 x 44 . . . perimeter = 968 x 22 . . . perimeter = 6016 x 11 . . . perimeter = 5413.266 x 13.266 . . . perimeter = 53.066All of these have an area of 176, but they all have different perimeters.The last one on the list is a square. That's the rectangle with the shortest possible perimeterthat has the area you want.The perimeter of this square is 53.066. You can make a rectangle with any perimetermore than that, and an area of 176.


What is Length of a rectangle with a perimeter of 88 meters and a width of 20 meters?

24 meters


What is the length of a rectangle if the width is 16 in and the area is 88 in?

It is: 88/16 = 5.5 feet


What are dimensions of a rectangle with a perimeter of 88 and a length that is 4 less than 5 times it's width?

8X36


What is the area in square millimeters of a rectangle with the width of 24 and the length of 88?

The answer depends on the units used for 24 and 88.


The length of a rectangle is 3 meters greater than the width The area is 88 meters 2 what are the dimensions of rectangle?

Come on! 88 = 11 x 8, end of story.


What is the area of a rectangle that is 11cm long and 8cm wide?

11 x 8 = 88


What is the work The length of a rectangle is 4 cm more than 3 times the width. The perimeter is 88 cm. What are the dimensions of the rectangle Write a system of equations based on the info?

Let its length be 3x+4 and its width be x Perimeter: 2*(3x+4+x) = 88 Solving the equation x = 10 Therefore: length = 34 cm and width = 10 cm Check: 2*(34+10) = 88 cm


If Perimeter of a rectangle that has a width of x inches and a length of x plus 16 inches is 2x plus 2x plus 16 inches simplify the expression for the perimeter Find the perimeter if x equals 14?

If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.


What is the area of a rectangle with a length of 11 inches and a width of 8 inches?

11 x 8 = 88 square inches (88 in2)


A magazine is 11 inches long and 8 inches wide what is the magazine's perimeter?

38 inches = perimeter 2*(w+l); 88 sq inches = Area (w*l)


What is the Angle of a regular rectangle?

88