A square of side 22 has an area of 484. Rectangle 23 x 21 has an area of 483...
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
An apothem of a regular polygon is a segment from its center to the midpoint of a side. You can use the apothem to find the area of a regular polygon using this formula: A = pa/2 where p is the perimeter of the figure and a is the apothem. For a regular octagon with side length 11, the perimeter p = 8(11) = 88. So the area would be A = 88(8.85)/2 = 389.4 square units.
Which quadrilateral? What is x?
The perimeter is L(length) x 2 + W(width) x 2 So 2L + 2W = 88 And L = W+4 So we can now replace the L in the equation and we get 2(W+4) + 2W = 88 Work out the brackets and we get 2W + 8 + 2 W = 88 Subtract 8 from both sides, and we get 2W + 2W = 80 or, 4W = 80 so we can divide both sides by 4 and we get W = 20 So now we can add 4 to the width and we get the length as 24. Now, to check the calculation, we add them all up Length 1 = 24 Length 2 = 24 Width 1 ==20 Width 2 ==20 Perimeter - 88
Let the length be x: 2(x+44) = 218 yards 2x+88 =218 2x = 218-88 2x = 130 x = 65 yards Check: 65+65+44+44 = 218 yards
You can't tell the perimeter from knowing the area.There are an infinite number of rectangles with different dimensions that all have the same area.Here are a few examples.1 x 176 . . . perimeter = 3542 x 88 . . . perimeter = 1804 x 44 . . . perimeter = 968 x 22 . . . perimeter = 6016 x 11 . . . perimeter = 5413.266 x 13.266 . . . perimeter = 53.066All of these have an area of 176, but they all have different perimeters.The last one on the list is a square. That's the rectangle with the shortest possible perimeterthat has the area you want.The perimeter of this square is 53.066. You can make a rectangle with any perimetermore than that, and an area of 176.
24 meters
It is: 88/16 = 5.5 feet
8X36
The answer depends on the units used for 24 and 88.
Come on! 88 = 11 x 8, end of story.
11 x 8 = 88
Let its length be 3x+4 and its width be x Perimeter: 2*(3x+4+x) = 88 Solving the equation x = 10 Therefore: length = 34 cm and width = 10 cm Check: 2*(34+10) = 88 cm
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
11 x 8 = 88 square inches (88 in2)
38 inches = perimeter 2*(w+l); 88 sq inches = Area (w*l)
88