A square with sides of 8 cm will have an area of 64 square cm.
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
12 square cm
The area of rectangle is : 24.0
64 done by paolo school cromer road
11 x 8 = 88
32 cm² = 8cm²/2
To get the area of a square, you square the length, ie area = LxL
8cm.
8cm * 8cm = 8*8 cm2 = 64 cm2
Divide the perimeter length by 4 ie 8cm and square the result ie 8cm x 8cm = 64sq cm
Area is 584.24cm² Perimeter is 88cm
55 square centimeters
94.985 or approximately 95 square centimeter.
pi*112 = 380 square cm
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
A square with sides of 8 cm will have an area of 64 square cm.