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i believe the answer to be 50.5... correct me if i am wrong
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∙ 12y ago
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What is the outlier of the mean median and mode?
The median and mode cannot be outliers. For small samples a mode could be an outlier.
How do you make a problem with mean median and mode?
mean is just if you sum up all samples and divide it by the number of samples median is the one in the middle. so you could sort your samples and then "delete the highest and lowest" until you only have one mode is the thing i can't remember
How do you calculate the error of a median for a non-parametric distribution?
You would need to take repeated samples, find their median and then calculate the standard error of these values.
An example where outliers affect mean but not median?
The sets of numbers {1, 1, 1, 1, 50} and {1, 1, 1, 1, 100} have this property. The median of both sets is 1 but the mean is 10.8 for the first set and 20.8 for the second.
Can two sets of data consist of different numbers but have the same mean median and mode?
one sample: 1, 2, 3, 3, 4, 5 another sample: -5, -2, 3, 3, 8, 11 These two samples have the same mean, median and mode. It's easy to make some of the elements of the samples different and keep the mean and median the same. However, since the mode is a most frequently observed value it has to be common to both samples. So to achieve a common mode some of the observed values must be the same.
What are six numbers where the mode is 100 and the mean is less than the median?
(1, 5, 97, 99, 100, 100) The mode is 100. The median is 98. The mean is 67.
What is the outlier of the mean median and mode?
The median and mode cannot be outliers. For small samples a mode could be an outlier.
What is the median for the counting numbers from 1 through 100?
50 half of 100 is 50
What is the median of 1 and 100?
It is 50.5 which is the number halfway between the two of them.
How do you make a problem with mean median and mode?
mean is just if you sum up all samples and divide it by the number of samples median is the one in the middle. so you could sort your samples and then "delete the highest and lowest" until you only have one mode is the thing i can't remember
How do you calculate the error of a median for a non-parametric distribution?
You would need to take repeated samples, find their median and then calculate the standard error of these values.
An example where outliers affect mean but not median?
The sets of numbers {1, 1, 1, 1, 50} and {1, 1, 1, 1, 100} have this property. The median of both sets is 1 but the mean is 10.8 for the first set and 20.8 for the second.
What is the median of 98 99 100 90 98 100?
The median is (98+99)/2 = 98.5
What is the median for 5 31 31 88 100?
Median is the middle number. The median is 31
What is the median of 45 and a 100?
Median of 45 and 100 = 145/2 = 72.5Median of 45 and 100 = 145/2 = 72.5Median of 45 and 100 = 145/2 = 72.5Median of 45 and 100 = 145/2 = 72.5
What is the median of all the square numbers to 100?
There are 10 square numbers from 1 to 100, so the median is the mean average of the middle two - the 5th and 6th square numbers = (25 + 36) ÷ 2 = 30.5
Can two sets of data consist of different numbers but have the same mean median and mode?
one sample: 1, 2, 3, 3, 4, 5 another sample: -5, -2, 3, 3, 8, 11 These two samples have the same mean, median and mode. It's easy to make some of the elements of the samples different and keep the mean and median the same. However, since the mode is a most frequently observed value it has to be common to both samples. So to achieve a common mode some of the observed values must be the same.
