Q: What is the median for the counting numbers from 1 through 100?

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The median is 50. Put the numbers in ascending numerical order: 40 45 48 52 61 65 For a set of numbers with an odd number of observations, the median would simply be the middle number. Because this set of numbers has an even number of observations, we take the middle two observations (48 and 52) and find their average. To find the average you add the observations and divide by the number of observations. In this case you would take 48 added to 52 and divide the sum of these numbers by 2. This gives you an answer of 50. (48 + 52 = 100 / 2 = 50)

90, 91,92,93,94,95,96,97,98,99,100. There are eleven terms. To find the median, you take the absolute middle term. The absolute middle term is '95'. NB You will notice that there are five terms to the left of 95, and five terms to the right of 95.

The first step in constructing a box-and-whisker plot is to first find the median, thelower quartile and the upper quartile of a given set of data. Example: The following set of numbers are the amount of marbles fifteen different boys own (they are arranged from least to greatest).18 27 34 52 54 59 61 68 78 82 85 87 91 93 100First find the median. The median is the value exactly in the middle of an ordered set of numbers. *68 is the medianNext, we consider only the values to the left of the median: 18 27 34 52 54 59 61. We now find the median of this set of numbers. Remember, the median is the value exactly in the middle oa an ordered set of numbers. Thus 52 is the median of the scores less than the median of all scores, and therefore is the lower quartile.52 is the lower quartileNow consider only the values to the right of the median: 78 82 85 87 91 93 100. We now find the median of this set of numbers. The median 87 is therefore called the upper quartile.87 is the upper quartile(*If you're finding the median in an ordered set with an even number of values, you must take the average of the two middle numbers. For example: 3, 5, 7, and 10. Add the two middle numbers. 5 + 7 = 12. Divided 12 by 2 to get the average. 12 / 2 = 6. Therefore 6 is the median for the ordered set of 3, 5, 7, and 10.)You are now ready to find the interquartile range (IQR).The interquartile range is the difference between the upper quartile and the lower quartile. In our case the IQR = 87 - 52 = 35. The IQR is a very useful measurement. It is useful because it is less influenced by extreme values, it limits the range to the middle 50% of the values.35 is the interquartile rangehere is a sucessful site called Jen's Box and Whisker plot, and here is a example of a whisker plot from that very own site. because itso hard to describe! i hope you find this helpful good luck!!

69, 78, 79, 88, 88, 92, 93, 95, 98, 100 The median is 90. The mode is 88. The mean is 88.

(76 + 100)/2 = 88

Related questions

Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.

The 3-digit counting numbers are 100 through 999 = 900 numbers.Half them are multiples of 2 (even numbers).The other half are not . . . 450 of them.

Counting numbers

100

The sum of the first 100 counting numbers (1-100) is 5,001.

8 numbers, so the median is the mean average of the 4th and 5th numbers. 4th number is 86 5th number is 86 median = (86 + 86) ÷ 2 = 86.

The median of those numbers is 90.

189 pennies.

4990

There are 10 square numbers from 1 to 100, so the median is the mean average of the middle two - the 5th and 6th square numbers = (25 + 36) ÷ 2 = 30.5

(1, 5, 97, 99, 100, 100) The mode is 100. The median is 98. The mean is 67.

90.5 is the median, as it is the number that is halfway between the two, or half of the total of the two numbers.