Q: What is the median of samples from 1 to 100?

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The median and mode cannot be outliers. For small samples a mode could be an outlier.

mean is just if you sum up all samples and divide it by the number of samples median is the one in the middle. so you could sort your samples and then "delete the highest and lowest" until you only have one mode is the thing i can't remember

You would need to take repeated samples, find their median and then calculate the standard error of these values.

The sets of numbers {1, 1, 1, 1, 50} and {1, 1, 1, 1, 100} have this property. The median of both sets is 1 but the mean is 10.8 for the first set and 20.8 for the second.

The median of 1 and 1 is 1.

Related questions

(1, 5, 97, 99, 100, 100) The mode is 100. The median is 98. The mean is 67.

50 half of 100 is 50

The median and mode cannot be outliers. For small samples a mode could be an outlier.

It is 50.5 which is the number halfway between the two of them.

mean is just if you sum up all samples and divide it by the number of samples median is the one in the middle. so you could sort your samples and then "delete the highest and lowest" until you only have one mode is the thing i can't remember

You would need to take repeated samples, find their median and then calculate the standard error of these values.

The sets of numbers {1, 1, 1, 1, 50} and {1, 1, 1, 1, 100} have this property. The median of both sets is 1 but the mean is 10.8 for the first set and 20.8 for the second.

The median is (98+99)/2 = 98.5

Median is the middle number. The median is 31

There are 10 square numbers from 1 to 100, so the median is the mean average of the middle two - the 5th and 6th square numbers = (25 + 36) ÷ 2 = 30.5

Median of 45 and 100 = 145/2 = 72.5Median of 45 and 100 = 145/2 = 72.5Median of 45 and 100 = 145/2 = 72.5Median of 45 and 100 = 145/2 = 72.5

one sample: 1, 2, 3, 3, 4, 5 another sample: -5, -2, 3, 3, 8, 11 These two samples have the same mean, median and mode. It's easy to make some of the elements of the samples different and keep the mean and median the same. However, since the mode is a most frequently observed value it has to be common to both samples. So to achieve a common mode some of the observed values must be the same.