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What is the midpoint of the line segment with endpoints (-17) and (3-3)?
Wiki User
∙ 8y ago
Points: (-12, -3) and (3, -8)
Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
Raphael Langosh
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What is the midpoint of the line segment with endpoints -17 and 3 -3?
If you mean endpoints of (-1, 7) and (3, -3) then the midpoint is (1, 2)
What is the length of the line segment with endpoints (-3 17) and (-3 -5)?
Endpoints: (-3, 17) and (-3, -5) Length of line: 22 units using the distance formula
What is the midpoint of the line segment with end point (-17) and (-33)?
If you mean points of (-1, 7) and (-3, 3) then the midpoint is at (-2, 5)
What is the midpoint of the line segment with endpoint (-17) and (3-3)?
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
What is the midpoint of the line segment with end points (-17) and (3-3)?
The mid point is the mean average of each coordinate → midpoint of (-1, 7) and (3, -3) is ((-1 + 3)/2, (7 + -3)/2) = (1, 2)
Both the red and blue line segments stretch from the center of the circle to a point on the circle The length of the blue line segment is 17 How long is the red line segment?
17
What is in its general form the perpendicular bisector equation meeting the line segment of s 2s and 3s 8s at its midpoint?
Points: (s, 2s) and (3s, 8s) Slope: 3 Perpendicular slope: -1/3 Midpoint: (2s, 5s) Equation in its general form: x+3y-17 = 0
The length of the blue line segment is 9 and the length of the red line segment is 17 How long is the major axis of the ellipse?
26
What is the length of the segment with endpoints A(17) B(-3-1)?
If you mean endpoints of (1, 7) and (-3, -1) then using the distance formula it is 4 times the square root of 5 which is about 9 units rounded to the nearest whole number.
Both the red and blue line segments stretch from the center of the circle to a point on the circle The length of the blue line segment is 17?
Every line segment between the center of a circle and any point on the circleis the same length as all the others.That length is called the 'radius' of that particular circle.
What is the perpendicular bisector equation that meets the line 13 19 and 23 17 at midpoint on the Cartesian plane showing all aspects of work with answer?
Points: (13, 19) and (23, 17) Midpoint: (18, 18) Slope: -1/5 Perpendicular slope: 5 Perpendicular equation: y-18 = 5(x-18) => y = 5x-72
What is the equation and its distance from origin that meets the line joining the points 13 17 and 19 23 at its midpoint on the Cartesian plane showing work?
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
