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Endpoints: (-3, 17) and (-3, -5)

Length of line: 22 units using the distance formula

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6y ago
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6y ago

It is 22.

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Q: What is the length of the line segment with endpoints (-3 17) and (-3 -5)?
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What is the midpoint of the line segment with endpoints -17 and 3 -3?

If you mean endpoints of (-1, 7) and (3, -3) then the midpoint is (1, 2)


The length of the blue line segment is 9 and the length of the red line segment is 17 How long is the major axis of the ellipse?

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Both the red and blue line segments stretch from the center of the circle to a point on the circle The length of the blue line segment is 17 How long is the red line segment?

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What is the midpoint of the line segment with endpoints (-17) and (3-3)?

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Both the red and blue line segments stretch from the center of the circle to a point on the circle The length of the blue line segment is 17?

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What is the length of the segment with endpoints A(17) B(-3-1)?

If you mean endpoints of (1, 7) and (-3, -1) then using the distance formula it is 4 times the square root of 5 which is about 9 units rounded to the nearest whole number.


Can a triangle has three sides of length 8 and 9 and 17?

The sides of 8 and 9 would have to stretch out straight in line in order to reach the ends of the side of 17, and then they would flop down right on top of it. The triangle would have two angles of zero degrees, and one angle of 180 degrees. When you looked at it, it would look like a straight line segment with a length of 17; you wouldn't know that there were two other line segments lying on top of it. A mathematician might call that a "degenerate triangle". But in a practical sense, I don't think anyone else would accept it as a member of the triangle club.


What is the length of the line segment of y equals 17 -3x that touches the curve of y equals x squared plus 2x -7 at points A and B showing all details of your homework?

If: y = x2+2x-7 and y = 17-3x Then it follows that: x2+2x-7 = 17-3x Subtract 17 and add 3x to both sides thus forming a quadratic equation: x2+5x-24 = 0 When factored: (x+8)(x-3) = 0 Therefore: x = -8 or x = 3 So when x = -8, y = 41 and when x = 3, y = 8 So the line touches the curve at points A(-8, 41) and B(3, 8) (x1-x2)2 + (y1-y2)2 = length of line segment2 (-8-3)2 + (41-8)2 = 1210 and the square root of this is 34.785 correct to 3dp Length of line segment = 34.785 units


What is the midpoint of the line segment with end point (-17) and (-33)?

If you mean points of (-1, 7) and (-3, 3) then the midpoint is at (-2, 5)


What is the midpoint of the line segment with endpoint (-17) and (3-3)?

Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)


What is the length of the line of y equals 17 -3x that spans the curve of y equals x squared plus 2x -7?

If you mean: y = 17-3x and y = x^2+2x-7 then the length of the line works out as 11 times square root of 10 or about 34.785 to three decimal places.


How do you find the length of the straight line y equals 17 -3x that joins the curve y equals x squared plus 2x -7?

First find the points where the straight line meets with the curve: x2+2x-7 = 17-3x x2+2x+3x-7-17 = 0 x2+5x-24 = 0 Solving the above by means of the quadratic equation formula gives x values of -8 and 3 when x = 3, y = 8 and when x = -8, y = 41 (x2-x1)2+(y2-y1)2 = (line length)2 (-8-3)2+(41-8)2 = 1210 and its square root is the length of the line Length = 11 times the square root of 10 which is about 34.785 units of length