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One is obviously out. Two is out because if two unequal forces n and p act on an object the resultant with the minimum force in magnitude is |n - p|, which will never be 0 if n =/= p. Three can be easily resolved with a quick example. Imagine an object with three concurrent forces acting on it. Two forces, n = 3 N and p = 4 N, create an angle with each other such that the resultant is 5 N. 180 degrees from the resultant, a force, r = 5 N, is acting on the object. Thus three unequal vectors on an object can result in 0.

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Q: What is the minimum number of unequal vectors that give a zero resultant?
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