First take the derivative: y' = 4x - 7
Now, solve for derivate equals zero:
4x - 7 = 0
4x = 7
x = 7/4
Locations where the derivative is zero may be a minimum, or a maximum, or neither (in this case it is indeed a minimum). Finally calculate the value of y for this particular value of x.
y = -9
+3 and -3
-1
There is no maximum but te minimum is 15.
Since the range of the cosine function is (-1,1), the function y = cos(x) assumes a minimum value of -1 for y.
y=2x2+5. Plug in 0 for x, and you get y=2(0)^2 +5 =0+5=5. 5 is the minimum value for y.
The curve turns at a minimum: (2.5, -12)
1.What are the equations of the two lines that define the maximum and minimum values for the graphs of y = sin x and y = cos x ?(1 point)(1 pt) y = 1 and y = -1(0 pts) y = 0(0 pts) y = 2 and y = -2(0 pts) y = 1 and y = 01 /1 point
a = 3 and y = 0
The vertex has a minimum value of (-4, -11)
if y = x2 + 1 Then the minimum value of y is 1, which happens at the point (0, 1). It lies in the domain of real numbers. i.e. {y | y ≥ 1, y ∈ ℝ}
The answer will depend on the ranges for x and y. If the ranges are not restricted, then C can have any value.