It is -5.
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
y = |x| - 2
y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.
you have to first find the derivative of the original function. You then make the derivative equal to zero and solve for x.
Since the range of the cosine function is (-1,1), the function y = cos(x) assumes a minimum value of -1 for y.
It has an absolute minimum at the point (2,3). It has no maximum but the ends of the graph both approach infinity.
It is -5.
When you look at the parabola if it opens downwards then the parabola has a maximum value (because it is the highest point on the graph) if it opens upward then the parabola has a minimum value (because it's the lowest possible point on the graph)
The [global] minimum.
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
y = -9
The only way that this could happen if enough of the data points have the same value at the minimum. The median is the middle number in a set of data points.So for example: {2,2,2,3,4}. The middle number is 2, which is also the minimum value.
If B=0, then the graph does not depend on the value of y. This is a vertical line at x = C/A
y = |x| - 2