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It is -5.
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
y = |x| - 2
y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.
Standard notation for a quadratic function: y= ax2 + bx + c which forms a parabola, a is positive , minimum value (parabola opens upwards on an x-y graph) a is negative, maximum value (parabola opens downward) See related link.
Since the range of the cosine function is (-1,1), the function y = cos(x) assumes a minimum value of -1 for y.
It has an absolute minimum at the point (2,3). It has no maximum but the ends of the graph both approach infinity.
It is -5.
When you look at the parabola if it opens downwards then the parabola has a maximum value (because it is the highest point on the graph) if it opens upward then the parabola has a minimum value (because it's the lowest possible point on the graph)
The [global] minimum.
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
y = -9
The only way that this could happen if enough of the data points have the same value at the minimum. The median is the middle number in a set of data points.So for example: {2,2,2,3,4}. The middle number is 2, which is also the minimum value.
If B=0, then the graph does not depend on the value of y. This is a vertical line at x = C/A
y = |x| - 2