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What is the minimum value of y in the function y equals 2x2 plus x-1?
Wiki User
∙ 13y ago
y = 2x^2 + x -1
If you know calculus you can find the minimum or maximum when the slope of the equation is zero. This is the first derivative of y with respect to x
dy/dx = 4x +1 = 0
4x = -1
x = -1/4
y = 2 (-1/4)^2 -1/4 -1 = 1/8-1/4-1 = 1/8 - 2/8 - 8/8 = -9/8 minimum = -1.125
Wiki User
∙ 13y ago
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