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What is the vertex of the parabola y equals x2 plus 8x plus 5?
Wiki User
∙ 12y ago
The vertex has a minimum value of (-4, -11)
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∙ 12y ago
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What is the vertex and line of symmetry of the parabola when y equals x2 -8x plus 1 taking pi as 3.142 showing work?
Forget about thw value of pi because it has nothing to do with the question. y = x2-8x+1 can be expressed as y = (x-4)2-15 Information about the vertex and line of symmetry can be extracted from the rearranged equation such as:- Vertex: (4, -15) Line of symmetry: x = 4
What is y equals x2-8x plus 3 in vertex form?
x^2-8x+3 = x^2-8x+16-16+3 = (x-4)^2-13 y=(x-4)^2 -13 The vertex is (4,-13).
Vertex of x2 plus 8x plus 15?
(-4,-1)
How do you write 8x plus 4y equals 5?
8x plus 4y equals 5 is 8x + 4y = 5.
-8x plus 3y equals -5 8x - 2y equals 6?
(1, 1)
What is x squared minus 8x plus 8y plus 32 equals 0 in standard parabola form?
7
What is the vertex and line of symmetry of the parabola when y equals x2 -8x plus 1 taking pi as 3.142 showing work?
Forget about thw value of pi because it has nothing to do with the question. y = x2-8x+1 can be expressed as y = (x-4)2-15 Information about the vertex and line of symmetry can be extracted from the rearranged equation such as:- Vertex: (4, -15) Line of symmetry: x = 4
What is y equals x2-8x plus 3 in vertex form?
x^2-8x+3 = x^2-8x+16-16+3 = (x-4)^2-13 y=(x-4)^2 -13 The vertex is (4,-13).
Y-8x plus 9y equals?
Y-8x plus 9y equals 10y-8x.
What is the y-coordinate of the vertex of a parabola with the following equation y equals x2 - 8x plus 18?
You can work this out by taking the derivative of the equation, and solving for zero: y = x2 - 8x + 18 y' = 2x - 8 0 = 2x - 8 x = 4 So the vertex occurs where x is equal to 4. You can then plug that back into the original equation to get the y-coordinate: y = 42 - 8(4) + 18 y = 16 - 32 + 18 y = 2 So the vertex of the parabola occurs at the point (4, 2), leaving 2 as the answer to your question.
Vertex of x2 plus 8x plus 15?
(-4,-1)
How do you write 8x plus 4y equals 5?
8x plus 4y equals 5 is 8x + 4y = 5.
What is the equivalent of the following equation y equals x2 - 8x plus 29?
The vertex form is y = (x - 4)2 + 13
What is the vertex of the function y equals x2-8x plus 12?
Y = X2 - 8X + 12set to 0X2- 8X + 12 = 0X2 - 8X = - 12halve the coefficient of the linear term, ( - 8 ), square it and add it to both sidesX2 - 8X + 16 = - 12 + 16factor on the left and gather term on the right(X - 4)2 = 4(X - 4)2 - 4 = 0================vertex form(4, - 4)=======vertex
Is y equals 8x-3 parallel to 8x plus y equals 3?
No.
What is the x value of -8x plus 8x plus 4 equals -24?
- 8x + 8x = 0 so question is meaningless.
What is the vertex of the function y equals 2 x 2 plus 8x plus 1?
If you meant, your two equations are y=2x+2 and y= 8x+1 your vertex will be at x=1/6 and y=7/3 you can plug these in and they will check out. but if you meant, y=(2x2) +8x+1 y=4+8x+1 y=8x+5 and then you only have one line so there will be no vertex. but the y intercept is at (0, 5) and your x-intercept at (-5/8, 0) if neither are these are what you are saying, sorry, and maybe try and repost and I will help you out.
