The question cannot be answered since there is no equation there!
229 apex
91
In the nuclear reaction (^{237}{93}Np \rightarrow ^{4}{2}He + ^{233}{91}Pa), the missing number is the mass number and atomic number of the parent nucleus minus the sum of the products. To find the missing mass number, subtract the sum of the products (4 + 233 = 237) from the parent nucleus (237), and for the atomic number, (93 - (2 + 91) = 0). Thus, the missing particle is an electron with mass number 0 and atomic number -1, which is represented as (^{0}{-1}e) for conservation of charge in the reaction.
Pasted in problem, which is simple addition. 229 229 229
Nuclear transmutation for uranium-233 (U-233) typically occurs when it absorbs a neutron and undergoes beta decay. In this process, U-233 can convert into thorium-233 (Th-233), which then decays into protactinium-233 (Pa-233) and eventually into stable uranium-233. This transformation is significant in nuclear reactions, especially in the context of breeding fuel in nuclear reactors.
The equation for the alpha decay of 233U is: 92233U --> 90229Th + 24He representing the alpha particle as a helium nucleus. 223U can also undergo fission, but since this is an rather unpredictable process, there is no standard equation.
Uranium-233 is not bad ! It is an important nuclear fuel . And also can be used in nuclear weapons.But it is radioactive and toxic as all uranium isotopes.
233
Non-Nuclear Futures has 233 pages.
Uranium 233 is an artificial isotope obtained only in a nuclear reactor from thorium 232 by the intermediate of a (n, gamma) nuclear reaction.
Now protactinium is obtained by a nuclear reaction:Th-232 + n------------Th-233--------------Pa-233
There is no missing number. The Fibonacci sequence continues: 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, ...