mode (most) = none
median (middle)= 6
range (subtract the biggest and smallest number together) = 12
Range: 34 Mean: 21.71 Median: 15 Mode: 10
(10, 12, 13, 17, 17, 18, 27) The median is 17. The mode is 17. The range is 17.
8, 8, 8, 10, 14, 15 The mean is 10.5 The median is 9. The mode is 8. The range is 7.
Mean: 7.44 Median: 7 Mode: 7 Range: 7
mean: 9 ordered sample: 7, 8, 8, 10, 12 median: 8 mode: 8 range: 12 - 7 = 5
Range: 34 Mean: 21.71 Median: 15 Mode: 10
Mean: 11.6 Median: 12 Mode: 10, 12, 15, 16, 5 Range: 11
Range: 25 Mean: 10 Median: 11 Mode: 11, 1
There cannot be such a set.If the mean is 10, the mode is 6 and the median is 9, the range must be at least 8.5.If the mode is 6, the median is 9 and the range is 8, the mean must be less than 9.8.
(10, 12, 13, 17, 17, 18, 27) The median is 17. The mode is 17. The range is 17.
The median is 8.5. The mode is 8. The range is 14.
8, 8, 8, 10, 14, 15 The mean is 10.5 The median is 9. The mode is 8. The range is 7.
Mean: 7.44 Median: 7 Mode: 7 Range: 7
Mean: 20.2222222 Median: 12 Mode: 11 Range: 79
There are 4 types of average that are commonly used: Mean, Mode, Median and Range. The Mean is all values added divided by number of values. In the case 4+10/2 = 7 The Mode is the most frequently occurring value. In this case there is no mode The Median is the middle value of all of the values. In this case the answer is 7 The range is the highest value minus the smallest value. In this case 10-4 = 6 Ajcollin
what i have is mean is 22.2,median which is the middle is 23,range is 26, and mode is 12
mean: 9 ordered sample: 7, 8, 8, 10, 12 median: 8 mode: 8 range: 12 - 7 = 5