0
It is 1 because it occurs most often
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∙ 9y ago
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What is the mode for 0 1 2 3 4 5 6?
What is the mode for 0 1 2 3 4 5 6 ?
What is the mode of 8 -6 4 9- 4 3 8 -1 4 2 5?
The mode is 4.
What is the mean median and mode for 3 4 2 1 1 6 8 1 1 3 2 2 10 12?
1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 8, 10, 12 The mean is 4 The median is 2.5 The mode is 1
What is the mode of 0 1 2 3 4 5 6 7 8?
That set has no mode.
What is the mode for this set of numbers 5 2 4 6 3 1?
there is no mode for this set of numbers
What is the mode for 0 1 2 3 4 5 6?
What is the mode for 0 1 2 3 4 5 6 ?
What is the mode for 6 8 1 4 6 0 4 3?
The mode is 6 and 4. Mode is the number that comes up the most. 6 and 4 have the highest of 2 for each of them.
What is the mode of 8 -6 4 9- 4 3 8 -1 4 2 5?
The mode is 4.
What is the mean median and mode for 3 4 2 1 1 6 8 1 1 3 2 2 10 12?
1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 8, 10, 12 The mean is 4 The median is 2.5 The mode is 1
What is 11 13 3 3 4 3 6 6 1 1 4 3?
A set of twelve numbers, with a mean value of 45/6, a median of 3, and a mode of 3.
What is the mode of 0 1 2 3 4 5 6 7 8?
That set has no mode.
What is the mode for this set of numbers 5 2 4 6 3 1?
there is no mode for this set of numbers
What is the mode of 6 3 1 6 6 2?
6 is the mode.
What if there is not a frequently listed number to find the mode?
Then there is no mode. There can only be a mode when there are more than on same number. No Mode: 45, 6, 21, 4, 765 Mode: 1, 4, 3, 4, 2,
What is the mean median mode and range of 1 3 6 7 1 3 6?
Mean: 3.857 Median: 3 Mode: 1, 3, 6 Range: 6
What is mode of 1 2 3 4 5 6 7 8 9 10 11?
That set has no mode.
How do you find mode if mean and median is given?
With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.
