The mode is 6 and 4. Mode is the number that comes up the most. 6 and 4 have the highest of 2 for each of them.
1 (0+1) 3 (0+1+2) 6 (0+1+2+3) 10 (0+1+2+3+4) 15 (0+1+2+3+4+5) 21 (0+1+2+3+4+5+6) Notice these are the numbers you can arrange into equalateral triangles.
The range of {0, 1, 2, 3, 4, 5, 6} is 6 - 0 = 6.
0.43 = (0 x 1) + (4/10) + (3/100)
If 3X - 4 ------ = 0 1-2X-4 So 3X - 4 ----- = 0 [ x (2X-3) ] 2X-3 3X-4 = 2X-3 [ -2X ] X - 4 = -3 [ +4 ] X= 1
It is {-1, 0, 1, 2, 3, 4, 5, 6, 7, 8}
What is the mode for 0 1 2 3 4 5 6 ?
That set has no mode.
there would be no mode because all numbers only occur once in the sequence.
The mode is the most common value in a set of data. A set of data may not have a mode (for example, if each value is listed once, then there is no mode since no one value is more common than another), or a set of data may have more than one mode (for example, if there are 3 different values that are each listed 5 times in a set of data, then each value is a mode). Example (no mode): {1, 2, 3, 4, 5} no mode Example (1 mode): {1, 1, 1, 2, 3, 4, 4, 5} mode is 1 Example (more than 1 mode): {1, 1, 1, 2, 3, 3, 4, 4, 4, 5} modes are 1 and 4 Example (more than 1 mode): {1, 1, 1, 2, 2, 2, 3, 3, 4, 4, 4, 5, 5, 5} modes are 1, 2, 4, 5
I was only able to get 13 but I think there can be more, this is what i got: 0+0+4=4 4+0+0=4 0+4+0=4 0+1+3=4 0+3+1=4 0+2+2=4 1+2+1=4 1+1+2=4 1+3+0=4 2+2+0=4 2+0+2=4 3+1+0=4 3+0+1=4
+4 +3 +3 -4 -3 -2 0 -1 +3 +1+1 0 +1
sides
2,2,0,5,1,4,1,3,0,0,1,4,4,0,1,4,3,4,2,1,0
The mode is 4.
It is a trimodal of 2, 3 and 4
0, 1, 4, 5, 6, 7, 8, 9, 9, 9, 11 mean = 6 and 3/11 median = 7 mode = 9
1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 8, 10, 12 The mean is 4 The median is 2.5 The mode is 1