The other name of an anti-derivative is an integral. An integral is the function which finds the area under a line. Let me give you an example. The integral of xn would be (xn+1/n+1)+C. So the integral of x2 would be (x3/3)+C. If you wanted to know what the area under the equation x2 when x=3 (in other words, all values of x between 0 and 3 on the x-axis), then you can do the equation ((3)3/3)+C and area would be 3 units squared. C is the constant of integration. For more info on C, you can go to http://en.wikipedia.org/wiki/Constant_of_integration or simply look it up
The antiderivative of 2x is x2.
The antiderivative of a function which is equal to 0 everywhere is a function equal to 0 everywhere.
Using u-substitution (where u = sinx), you'll find the antiderivative to be 0.5*sin2x + C.
I assume you mean -10x^4? In that case, antiderivative would be to add one to the exponent, then divide by the exponent. So -10x^5, then divide by 5. So the antiderivative is -2x^5.
Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C
By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2
The fundamental theorum of calculus states that a definite integral from a to b is equivalent to the antiderivative's expression of b minus the antiderivative expression of a.
(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)
The antiderivative of a constant, such as (8\pi), is found by multiplying the constant by the variable of integration and adding a constant of integration (C). Thus, the antiderivative of (8\pi) with respect to (x) is (8\pi x + C), where (C) represents any constant.
It is -exp (-x) + C.
-e-x + C.
X(logX-1) + C