If the rectangle is 12 feet long and has a perimeter of 40, then the height must be 8.
If it is made 6 feet longer, it will have a length of 18 and a height of 8. The new area will be 144.
find the perimeter and area of a rectangle that is 15cm long and 5cm wide
what is the perimeter and area of a rectangle 3cm long and 3cm wide
Without further information it is impossible to say (exactly): If the rectangle was 0.5 x 6.5, its perimeter is 14 units and its area is 3.25 units2 If the rectangle was 1 x 6, its perimeter is 14 units and its area is 6 units2 If the rectangle was 2 x 5, its perimeter is 14 units and its area is 10 units2 If the rectangle was 3 x 4, its perimeter is 14 units and its area is 12 units2 If the rectangle was 3.5 x 3.5, its perimeter is 14 units and its area is 12.25 units2 (and it's a square). It all depends upon the lengths of the longer and shorter sides of the rectangle: as long as 2 x longer + 2 x shorter = 14, any area greater than 0 units2 and less than or equal to 12.25 units2 can be made.
Width of rectangle: 144/18 = 8cm Perimeter of rectangle: 2*(18+8) = 52cm
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
A 9 x 1 rectangle has a perimeter of 20 and an area of 9; A 9.5 x 0.5 rectangle has the same perimeter but an area of 4.75; You can go a long way along this road...
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
The rectangle is 6-ft long and 4-ft wide.
Perimeter: 7+3+7+3 = 20 inches Area: 7 times 3 = 21 square inches
Perimeter is the length of a closed line around an area. A rectangle is an area. If each long side of the rectangle is 12 cm and each end of the rectangle is 9 cm, the total length is 14+14+9+9 or 46 cm.
The perimeter is 2L + 2W. The area is L x W. As long as you have one of those values, you should be able to solve for the other one.
Perimeter = 154 mm = 15.4 cmArea = 1,372 mm2 = 13.72 cm2