This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
2L + 2W = 34 L + W = 17 L = 2W - 4 3W - 4 = 17 3W = 21 W = 7 L = 10
A regular hexagon is a shape that has 6 equal sides. x = length of a side 6x = perimeter of hexagon pond
You need to write two equations with two variables each, for the two facts. Remembering that the perimeter is the sum of the lengths of all the sides:Write an equation for the perimeter of the original rectangle:perimeter = 2(length + width)26 = 2(l+w) (equation 1)Write an equation for the area of the increased rectangle:A = length x widthA = (l+4)(w+3) (equation 2)Solve the two equations simultaneously; and you'll get the width and length of the original rectangle.
p = pi x 2r
Having the length x meters and width 8 meters, then the area is 8x square meters.
Write an equation for the perimeter, and solve it. Remember that the perimeter is the sum of all four sides.
#include<stdio.h> void main() { float length, breadth, area, perimeter; printf("Enter the length & breadth of a Rectangle\n(length breadth): "); scanf("%f %f",&length,&breadth); area=length*breadth; perimeter=2*(length+breadth); printf(" Area of the Rectangle=%0.3f\n",area); printf("Perimeter of the Rectangle=%0.3f\n",perimeter); printf("(Press ENTER to exit.)"); getch(); printf("\n"); }
The area of rectangle is : 896.0
The perimeter of a rectangle is the sum of the four sides.
6x-14
The perimeter of a rectangle, like the perimeter of any closed two-dimensional figure, is the distance around it. The perimeter of the rectangle is the sum of two lengths plus two widths.
p=2l+2w
PRINT "Give me the rectangle's length.": Input L PRINT "Give me the rectangle's width.": Input W PRINT "The rectangle's area is "; L x W PRINT "The rectangle's perimeter is "; 2 x (L + W) PRINT "You've been a great audience. I'm here til Thursday. Don't forget to tip your waiter. Have a nice day."
Rectangles have 4 sides Rectangles have 4 90 degree angles A rectangle's area can be found by multiplying it's length by it's height. A rectangle's perimeter can be found by adding all of it's sides together.
The area of a rectangle with a width of x units and a length of (x + 3) units
The area of rectangle is : 13832.797999999999
The perimeter of a polygon is simply the sum of the lengths of its sides. There is no polynomial that expresses that for all polygons, but the perimeter of a rectangle is P=2(L+H) where P is the perimeter, L is the length, and H is the height.