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What faces make up the net of a triangular prism?
Four triangles and a square base! * * * * * Obviously answered by someone who does not know the difference between a prism and a pyramid. The net for a triangular prism is made up of two triangles and three rectangles. If the sides of the triangle are of length a, b and c and the length of the prism is l units, then the rectangles are a x l, b x l and c x l.
What is the volume of the triangular prism if there are four numbers on the shape?
Assuming that the prism is a right triangular prism and that the 3 of the numbers are the lengths of the sides of the triangle, and the 4th is the length of the prism,Suppose the sides of the triangle are a, b and c units and let s = (a+b+c)/2then area of the triangle = sqrt[s*(s-a)*(s-b)*(s-c)]and so, if the length of the prism is d,its volume = d*sqrt[s*(s-a)*(s-b)*(s-c)]
What is the surface area triangular prism?
If the sides of the triangular base are a, b and c and the height is h, the area is 2sh + 2 sqrt (s(s-a)(s-b)(s-c)) where s = (a +b +c)/2 [I. e. s is the semiperimeter of the base] and sqrt means"the square root of "
What is the formula for area of base of a triangular prism?
One possible form is sqrt{s*(s-a)*(s-b)*(s-c)} square units where the lengths of the three sides of the triangle are a, b and c units and s = (a+b+c)/2.
What is the formula for the surface area and volume of a triangular prism?
The answer depends on the information that you do have. Suppose you know all the edge lengths: the three sides of the triangle are a, b and c and the length of the prism is d. Let s = (a + b + c)/2 Then the area of the triangular cross section is sqrt[s*(s-a)*(s-b)*(s-c)] square units. So, surface area = 2*sqrt[s*(s-a)*(s-b)*(s-c)] + d*(a+b+c) square units. Volume = sqrt[s*(s-a)*(s-b)*(s-c)]*d cubic units.
What faces make up the net of a triangular prism?
Four triangles and a square base! * * * * * Obviously answered by someone who does not know the difference between a prism and a pyramid. The net for a triangular prism is made up of two triangles and three rectangles. If the sides of the triangle are of length a, b and c and the length of the prism is l units, then the rectangles are a x l, b x l and c x l.
What shape that has 2 triangular faces and 3 rectangular faces?
A triangular prism.... like the Toblerone chocolate box.... a triangle at each end. Label the angles A, B and C at one end and A1, B1 and C1 at the other end. Now, there are three rectangles - A, A1, B, B1 - A, A1, C, C1 - B, B1, C, C1
What is the volume of the triangular prism if there are four numbers on the shape?
Assuming that the prism is a right triangular prism and that the 3 of the numbers are the lengths of the sides of the triangle, and the 4th is the length of the prism,Suppose the sides of the triangle are a, b and c units and let s = (a+b+c)/2then area of the triangle = sqrt[s*(s-a)*(s-b)*(s-c)]and so, if the length of the prism is d,its volume = d*sqrt[s*(s-a)*(s-b)*(s-c)]
What is the surface area triangular prism?
If the sides of the triangular base are a, b and c and the height is h, the area is 2sh + 2 sqrt (s(s-a)(s-b)(s-c)) where s = (a +b +c)/2 [I. e. s is the semiperimeter of the base] and sqrt means"the square root of "
What is the formula for the area of a triangular prism?
If the sides of the triangle are a, b and c and the length is d, then, area of triangular cross section t = sqrt[s*(s-a)*(s-b)*(s-c)] square units where s = (a+b+c)/2 and then total area = 2*t + (a+b+c)*d suare units = 2t + 2sd square units.
How do you find the surface and lateral area of a triangular prism?
If the bases have sides of length a, b and c units and the length of the prism is d units thenlateral area = (a+b+c)*darea of base = sqrt{s*(s-a)*(s-b*(s-c)} where s = (a+b+c)/2Then total surface area = lateral area + 2*area of base.
What is the formula for the area of base in a triangular prism?
One possible form is sqrt{s*(s-a)*(s-b)*(s-c)} square units where the lengths of the three sides of the triangle are a, b and c units and s = (a+b+c)/2.
What is the formula for area of base of a triangular prism?
One possible form is sqrt{s*(s-a)*(s-b)*(s-c)} square units where the lengths of the three sides of the triangle are a, b and c units and s = (a+b+c)/2.
What is the formula for the surface area and volume of a triangular prism?
The answer depends on the information that you do have. Suppose you know all the edge lengths: the three sides of the triangle are a, b and c and the length of the prism is d. Let s = (a + b + c)/2 Then the area of the triangular cross section is sqrt[s*(s-a)*(s-b)*(s-c)] square units. So, surface area = 2*sqrt[s*(s-a)*(s-b)*(s-c)] + d*(a+b+c) square units. Volume = sqrt[s*(s-a)*(s-b)*(s-c)]*d cubic units.
How can you figure out the way to find the surface area for a triangular prism?
SA = 2B + Ph SA = 2(1/2ab) + (b + c + d)h SA = ab + (b + c + d)h
What is the c in the formula for finding surface area of trapezoidal prism?
You must be thinking of a triangular prism. In that case, c is the length of the third side of the triangle at the end of the prism.
What is the surface area of a triangular prism?
For an irregular rectangular prism,the total surface area is BH + (s1 + s2 + s3)L whereB is the baseH the heightL the lengths1 s2 s3 the sidesFor a regular triangular prism,the total area is 3 BL + BH(The sides are 3 x base x length. The ends are 2 x 1/2 base x height.)first of all its not triangular prismits a prism whose base is a trianglelateral surface area = perimeter of the base (sum of sides of the triangular base) x height(length) of the prismtotal surface area = lateral surface area + 2 x area of basefor area of base use the formula{whole root over [s(s-a)(s-b)(s-c)]}where a, b, c are the sides of the base triangleand s = [(a+b+c)/2]
