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The net of a triangular prism consists of two triangular faces and three rectangular faces. When unfolded, the triangles form the ends of the prism, while the rectangles connect the corresponding sides of the triangles. The arrangement of these shapes can vary, but they will always consist of these five faces. If you have specific options (a, b, c, or d), please provide them for a more tailored response.

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What faces make up the net of a triangular prism?

Four triangles and a square base! * * * * * Obviously answered by someone who does not know the difference between a prism and a pyramid. The net for a triangular prism is made up of two triangles and three rectangles. If the sides of the triangle are of length a, b and c and the length of the prism is l units, then the rectangles are a x l, b x l and c x l.


What is the volume of the triangular prism if there are four numbers on the shape?

Assuming that the prism is a right triangular prism and that the 3 of the numbers are the lengths of the sides of the triangle, and the 4th is the length of the prism,Suppose the sides of the triangle are a, b and c units and let s = (a+b+c)/2then area of the triangle = sqrt[s*(s-a)*(s-b)*(s-c)]and so, if the length of the prism is d,its volume = d*sqrt[s*(s-a)*(s-b)*(s-c)]


What is the surface area triangular prism?

If the sides of the triangular base are a, b and c and the height is h, the area is 2sh + 2 sqrt (s(s-a)(s-b)(s-c)) where s = (a +b +c)/2 [I. e. s is the semiperimeter of the base] and sqrt means"the square root of "


What is the formula for area of base of a triangular prism?

One possible form is sqrt{s*(s-a)*(s-b)*(s-c)} square units where the lengths of the three sides of the triangle are a, b and c units and s = (a+b+c)/2.


What is the formula for the surface area and volume of a triangular prism?

The answer depends on the information that you do have. Suppose you know all the edge lengths: the three sides of the triangle are a, b and c and the length of the prism is d. Let s = (a + b + c)/2 Then the area of the triangular cross section is sqrt[s*(s-a)*(s-b)*(s-c)] square units. So, surface area = 2*sqrt[s*(s-a)*(s-b)*(s-c)] + d*(a+b+c) square units. Volume = sqrt[s*(s-a)*(s-b)*(s-c)]*d cubic units.

Related Questions

What faces make up the net of a triangular prism?

Four triangles and a square base! * * * * * Obviously answered by someone who does not know the difference between a prism and a pyramid. The net for a triangular prism is made up of two triangles and three rectangles. If the sides of the triangle are of length a, b and c and the length of the prism is l units, then the rectangles are a x l, b x l and c x l.


What is the volume of the triangular prism if there are four numbers on the shape?

Assuming that the prism is a right triangular prism and that the 3 of the numbers are the lengths of the sides of the triangle, and the 4th is the length of the prism,Suppose the sides of the triangle are a, b and c units and let s = (a+b+c)/2then area of the triangle = sqrt[s*(s-a)*(s-b)*(s-c)]and so, if the length of the prism is d,its volume = d*sqrt[s*(s-a)*(s-b)*(s-c)]


What is the surface area triangular prism?

If the sides of the triangular base are a, b and c and the height is h, the area is 2sh + 2 sqrt (s(s-a)(s-b)(s-c)) where s = (a +b +c)/2 [I. e. s is the semiperimeter of the base] and sqrt means"the square root of "


What is the formula for the area of a triangular prism?

If the sides of the triangle are a, b and c and the length is d, then, area of triangular cross section t = sqrt[s*(s-a)*(s-b)*(s-c)] square units where s = (a+b+c)/2 and then total area = 2*t + (a+b+c)*d suare units = 2t + 2sd square units.


How do you find the surface and lateral area of a triangular prism?

If the bases have sides of length a, b and c units and the length of the prism is d units thenlateral area = (a+b+c)*darea of base = sqrt{s*(s-a)*(s-b*(s-c)} where s = (a+b+c)/2Then total surface area = lateral area + 2*area of base.


What shape that has 2 triangular faces and 3 rectangular faces?

A triangular prism.... like the Toblerone chocolate box.... a triangle at each end. Label the angles A, B and C at one end and A1, B1 and C1 at the other end. Now, there are three rectangles - A, A1, B, B1 - A, A1, C, C1 - B, B1, C, C1


What is the formula for area of base of a triangular prism?

One possible form is sqrt{s*(s-a)*(s-b)*(s-c)} square units where the lengths of the three sides of the triangle are a, b and c units and s = (a+b+c)/2.


What is the formula for the area of base in a triangular prism?

One possible form is sqrt{s*(s-a)*(s-b)*(s-c)} square units where the lengths of the three sides of the triangle are a, b and c units and s = (a+b+c)/2.


What is the formula for the surface area and volume of a triangular prism?

The answer depends on the information that you do have. Suppose you know all the edge lengths: the three sides of the triangle are a, b and c and the length of the prism is d. Let s = (a + b + c)/2 Then the area of the triangular cross section is sqrt[s*(s-a)*(s-b)*(s-c)] square units. So, surface area = 2*sqrt[s*(s-a)*(s-b)*(s-c)] + d*(a+b+c) square units. Volume = sqrt[s*(s-a)*(s-b)*(s-c)]*d cubic units.


How can you figure out the way to find the surface area for a triangular prism?

SA = 2B + Ph SA = 2(1/2ab) + (b + c + d)h SA = ab + (b + c + d)h


What is the c in the formula for finding surface area of trapezoidal prism?

You must be thinking of a triangular prism. In that case, c is the length of the third side of the triangle at the end of the prism.


What is the surface area of a triangular prism?

For an irregular rectangular prism,the total surface area is BH + (s1 + s2 + s3)L whereB is the baseH the heightL the lengths1 s2 s3 the sidesFor a regular triangular prism,the total area is 3 BL + BH(The sides are 3 x base x length. The ends are 2 x 1/2 base x height.)first of all its not triangular prismits a prism whose base is a trianglelateral surface area = perimeter of the base (sum of sides of the triangular base) x height(length) of the prismtotal surface area = lateral surface area + 2 x area of basefor area of base use the formula{whole root over [s(s-a)(s-b)(s-c)]}where a, b, c are the sides of the base triangleand s = [(a+b+c)/2]