The nth root of a number is a number such that if you multiply it by itself (n-1) times you get the number. Or if you multiply 1 by it n times. Many definitions get this wrong due to sloppy use of the language.So if y^n = x then the nth root of x is y.
x^(a/b) is the bth root of x^a or, equivalently, it is (bth root of x)^a. If mental calculation is required then the second form is easier to use because it means you are dealing with smaller number. For example, 16^(3/4) can be calculated as (4th root of 16)^3 = 2^3 = 8. Not too difficult. But the alternative method would be to calculate the 4th root of 16^3 = the fourth root of 4096. Not something most people would wish to tackle.
A negative root is simply the reciprocal. Thus x^(-a) is simply 1/(x^a).
No. In general, the square root of a negative number is an imaginary number, which is not a real number.
If you want a real number as an answer, then there is no solution - no real number squared will give you a negative result. If complex numbers are acceptable, just take the square root of the positive number, and add an "i" at the end. For example, the square root of (-4) is 2i. Whether or not a complex number is acceptable depends on the kind of problem. The same happens for negative and fractional numbers; for some problems, a negative number is acceptable as an answer, for others not.
You cannot get real square root of a negative number because two numbers multiplied by themselves are always positive You can always get a real cube root of a negative number because three negative numbers multiplied by themselves give a negative .
The square root of a negative number is not real.
There is no real number [square] root of a negative number. There is a real cube root and a real fiftth root etc, but root, by itself, implies square root.
No, it is not, because real numbers include negative numbers. The square root of a negative number is an imaginary number
It depends on the combination. Real numbers are closed with respect to arithmetical operations (+, -, *, /), as well as integer powers (exponents). So a combination of real numbers using any of these operators will yield a real number. But the set is not closed with respect to some fractional powers - for example, the square root of a negative number is not real.It depends on the combination. Real numbers are closed with respect to arithmetical operations (+, -, *, /), as well as integer powers (exponents). So a combination of real numbers using any of these operators will yield a real number. But the set is not closed with respect to some fractional powers - for example, the square root of a negative number is not real.It depends on the combination. Real numbers are closed with respect to arithmetical operations (+, -, *, /), as well as integer powers (exponents). So a combination of real numbers using any of these operators will yield a real number. But the set is not closed with respect to some fractional powers - for example, the square root of a negative number is not real.It depends on the combination. Real numbers are closed with respect to arithmetical operations (+, -, *, /), as well as integer powers (exponents). So a combination of real numbers using any of these operators will yield a real number. But the set is not closed with respect to some fractional powers - for example, the square root of a negative number is not real.
Imaginary number
The square root of a negative number is considered an imaginary number, denoted as "i". In this case, the square root of -3 would be √(-3) = √3 * i. Therefore, the square root of -3 is not a real number, as real numbers are those that can be represented on the number line without involving "i".
Yes. In general, the square root of any non-negative number is a real number.
The square root of 100 is rational since it is not repeating.
It's irrational/not a real number