Q: What is the nth term of 1 7 17 31 49?

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+9

-n2+2n+49

The Least Common Multiple (LCM) for 17 31 49 is 25,823

7n

There are infinitely many possible answers. the simplest polynomial is Un = -n4 + 12n3 - 47n2 + 78n - 41

3n2 + 1Hope this helps :)

The next number in the sequence is a multiple of the number times seven, so the nth term would be 7n . 71 = 7 72 = 49 73 = 343 74 = 2,401 75 = 16,807 76 = 117,649 etc.

t(n) = n2 + 5n - 1

The difference between successive terms is 8 tn = 8n + 9 or 8(n+1)+1 where n = 1,2,3,...

31% of 49= 31% * 49= 0.31 * 49= 15.19

49

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The factors of 31 are: 1, 31 The factors of 49 are: 1, 7, 49

31 x 49 = 1519

39 = 3 x 13 49 = 7 x 7 51 = 3 x 17 43 is prime 31 is prime

Factors of 49: 1, 7, 49Factors of 17: 1, 17GCF (49, 17) = 1

31/49 doesn't simplify as 31 is a prime number.

f = 10n + (n - 1)^2 For n=10 f = 10(10) + (10 - 1)^2 f = 181

31 is a prime number and has no factors other than 1 and itself. The factors of 49 are 1, 7, and 49.

It is 17/49

This can be found out by using the formula for sum of n terms of an arithmetic progression. here, n is not known. a=2 d=2 (since it's even) nth term=98 (last even number less than 100) using formula for nth term, nth term=a+(n-1)d 98=2+(n-1)2 therefore, n=49 so, sum of n terms=n/2[2*a+(n-1)d] putting n=49, a=2, and d=2, sum=2450

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37 41, 43, and 47.

Their product.

Each consecutive terms is increased by 8 and so the next term is 49

49 + 66 + 132 + 31 = 278