To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
-n2+2n+49
13/49 is in its lowest terms
31% of 49= 31% * 49= 0.31 * 49= 15.19
f = 10n + (n - 1)^2 For n=10 f = 10(10) + (10 - 1)^2 f = 181
+9
2n^2-1
t(n) = n2 + 5n - 1
-n2+2n+49
7n
(Term)n = 59 - 2n
To find the nth term of a sequence, we first need to determine the pattern or rule that governs the sequence. In this case, the sequence appears to be increasing by adding consecutive odd numbers: 3, 6, 9, 12, and so on. Therefore, the nth term formula for this sequence is Tn = 3n^2 + n. So, the nth term for the sequence 4, 7, 13, 22, 34 is Tn = 3n^2 + n.
13/49 is in its lowest terms
The next number in the sequence is a multiple of the number times seven, so the nth term would be 7n . 71 = 7 72 = 49 73 = 343 74 = 2,401 75 = 16,807 76 = 117,649 etc.
fsedaz sd
31% of 49= 31% * 49= 0.31 * 49= 15.19
9 = 13 - 4 = 22 - 13 = 31 - 22 = 40 - 31 next are 49 58 67 76 85 94 and so on ...