t(n) = n2 + 5n - 1
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
It is 6n+5 and so the next term will be 35
a (sub n) = 35 - (n - 1) x d
n + 6 * * * * * I suggest you try t(n) = 6n + 5 instead.
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
It is 6n+5 and so the next term will be 35
It is: nth term = 35-9n
a (sub n) = 35 - (n - 1) x d
n + 6 * * * * * I suggest you try t(n) = 6n + 5 instead.
The given sequence (7, 14, 21, 28, 35,....) is an arithmetic sequence where each term increases by 7. The nth term of the given sequence is 7n
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
To find the nth term of the sequence 0, 3, 8, 15, 24, 35, we can observe the pattern in the differences between consecutive terms. The differences are 3, 5, 7, 9, 11, which form an arithmetic sequence with a common difference of 2. This suggests that the nth term can be represented by the formula ( n^2 - n ), where n starts from 1. Thus, the nth term for the given sequence is ( n^2 - n ).
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
(n+1)2-1
tn = 2x2 + 3 where x = 1, 2, 3, ...
To find the nth term of the quadratic sequence 3, 8, 15, 24, 35, we first identify the differences between the terms: 5, 7, 9, 11, which indicates a second difference of 2. This suggests the sequence can be represented by a quadratic formula of the form ( an^2 + bn + c ). By solving the equations formed using the first few terms, we find the nth term to be ( n^2 + 2n ). Thus, the nth term of the sequence is ( n^2 + 2n ).