If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128
The nth term is 2n
the nth term for 1 2 4 8 16 32 is 2 to the power n-1. I cannot type superscript. It look like a big 2 and then n-1 where we put small number on the top right hand.
The n-th term would be: 2^(6-n) So, when n=1, it is 2^(6-1) = 2^5 = 32.
If you meant: 2 12 22 32 then the nth term = 10n-8
The Nth term in the series is [ 2N ] .
The nth term is 9n-2
The answer is 128/(2^(n-1)) if the 1st term is 128. The divisor is found by the realization that these are decreasing powers of two.
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
2 raised to the power of n+1. In other words 2 multiplied by itself n+1 times.
The nth term is 7n-5 and so the 6th term will be 37
It is: nth term = -4n+14
The nth term = 9n-2
The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)
n2 + 3n - 2
The sequence is 2 larger than the 7 times table. The nth term can be expressed as 7n + 2.
It is: -6n+22
square of (n x 2)
n^2 + 2n + 1
Un = 29 - 9n