The answer is 128/(2^(n-1)) if the 1st term is 128. The divisor is found by the realization that these are decreasing powers of two.
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The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)
128 + 0 + 32 + 16 + 0 + 4 + 0 + 1 = 181
The LCM is: 128
It is: 128/4 = 32 and 32*32 = 1024 square cm
The factors of 512 are: 1 2 4 8 16 32 64 128 256 512So: 1·2·256 = 5121·4·128 = 5121·8·64 = 5121·16·32 = 5122·4·64 = 5122·8·32 = 5124·8·16 = 512