the nth term for 1 2 4 8 16 32 is 2 to the power n-1. I cannot type superscript. It look like a big 2 and then n-1 where we put small number on the top right hand.
The nth term is: 3n+1 and so the next number will be 16
We note the sequence goes up in steps of '8' Hence '8n'. Next for step #1 4#1 ; n = 1 ; 8(1) + c = 16 8 + c = 16 c = 8 Hence the nth terms is 8n + 8 Verifications When n = 3 ; 8(3) + 8 = 24 + 8 = 32 ( which is true).
The nth term is n2.
5n+1
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The nth term is: 3n+1 and so the next number will be 16
The answer is 128/(2^(n-1)) if the 1st term is 128. The divisor is found by the realization that these are decreasing powers of two.
We note the sequence goes up in steps of '8' Hence '8n'. Next for step #1 4#1 ; n = 1 ; 8(1) + c = 16 8 + c = 16 c = 8 Hence the nth terms is 8n + 8 Verifications When n = 3 ; 8(3) + 8 = 24 + 8 = 32 ( which is true).
Clearly, if you omit the sign, the nth. term will be 4n. The alternating sign can easily be expressed as a power of (-1), so in summary, the nth. term is (-1)n4n.
The nth term is 22n and so the next number will be 5*22 = 110
The nth term is n2.
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
5n+1
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
2n+1
n2
t(3) = 10 - 32 = 1