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Q: What is the nth term of 5 7 9?

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The nth term of the sequence is 2n + 1.

Un = 4n - 9

The "N"th term is -7. You can deduce this from: 19 - 7 = 12 - 7 = 5 - 7 = -2 - 7 = -9

7 - 4n where n denotes the nth term and n starting with 0

For an A.P., nth term of the sequence is given by 5 + (n-1)d, where d is the common difference.

It is: nth term = 7n-9

2n + 1

I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7

The nth term is 7n-5 and so the 6th term will be 37

2n+5

The nth term is: 2n+7 and so the next number will be 19

Un = (-1)n*(2n - 1)

The nth term is 25-4n and so the next term will be 5

The nth term is 2n+5 and so the next number is 17

IT is A.P. Arithmetic progressionFormula to solven th term = First_term + ( n - 1)*difference_between_two_non=9first term=7difference_between_two_no = nth_term - (n-1)th_term = 5-7 = 3-5 =1-3 = -2nth term = 7+8*(-2) = -9Another Answer:-The nth term = 9-2n

Un = 4n - 13.

fu

t(n) = 5 - 7n for n = 1, 2, 3, ... The difference between each term is -7, therefore the nth term will be: t(n) = -2 + -7 × (n - 1) = -2 + 7n + 7 = 5 - 7n

The answer depends on the value of B.

Clearly here the nth term isn't n25.

(2n-1)(-1)n

It is 4n-13 and so the next number will be 11

n+4

Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.

The nth term is 4n - 3