To find the nth term in a quadratic sequence, we first need to determine the pattern. In this case, the difference between consecutive terms is increasing by 3, 5, 7, 9, and so on. This indicates a quadratic sequence. To find the 9th term, we need to use the formula for the nth term of a quadratic sequence, which is given by: Tn = an^2 + bn + c. By plugging in n=9 and solving for the 9th term, we can find that the 9th term in this quadratic sequence is 74.
n2 + 3n - 2
Well, darling, the first 5 terms in that fancy sequence are 28, 26, 24, 22, and 20. You get those numbers by plugging in n values 1 through 5 into the formula 30-2n. So, there you have it, sweet cheeks!
First put them in order:11, 12, 13, 15, 16, 26, 26.Then use your fingers the numbers at the opposite ends:11, 12, 13, 15, 16, 26, 26.Then keep moving in11, 12, 13, 15, 16, 26, 26.11, 12, 13, 15, 16, 26, 26.Until you come to the middle:11, 12, 13, 15, 16, 26, 26.So the median is 15.
There are infinitely many polynomials of order 6 (or higher) that will give these as the first six numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.In this particular case, the simplest solution isU(n) = 3*n^2 - 1 for n = 1, 2, 3, ...
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
Expressed in terms of n, the nth term is equal to 7n - 2.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: nth term = 35-9n
46n9
Tn = 10 + n2
Well, isn't that just a lovely pattern we have here? Each term is increasing by 4, isn't that delightful? So, if we want to find the nth term, we can use the formula: nth term = first term + (n-1) * common difference. Just like painting a happy little tree, we can plug in the values and find the nth term with ease.
[ 6n + 8 ] is.
It is: 26-6n
The common difference (d) between successive terms is -9. The first term (a) is 26 The formula for the nth term [a(n)] of an Arithmetic Series is , a + (n - 1)d. Inputting the values for a and d gives :- a(n) = 26 - 9(n - 1) = 26 - 9n + 9 = 35 - 9n......where n = 1,2,3......
t(n) = 4n2 - 4n + 2
8 + (74 x 6) = 75th term. nth term = 8 + 6(n-1)