Un = (-1)n*(2n - 1)
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
It is: nth term = 5-4n and so the next term will be -19
The sequence 3, 7, 11, 15 is an arithmetic sequence where each term increases by 4. The first term (a) is 3, and the common difference (d) is 4. The nth term can be expressed using the formula: ( a_n = a + (n - 1)d ). Substituting the values, the nth term is ( a_n = 3 + (n - 1) \cdot 4 = 4n - 1 ).
The nth term is: 5-2n
The sequence 2, 5, 8, 11 is an arithmetic sequence where the first term is 2 and the common difference is 3. The nth term can be expressed using the formula: ( a_n = 2 + (n - 1) \cdot 3 ). Simplifying this gives ( a_n = 3n - 1 ). Thus, the nth term is ( 3n - 1 ).
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
The nth term of the sequence is 2n + 1.
It is: nth term = 5-4n and so the next term will be -19
The nth term is 4n-1 and so the next term will be 19
11
1...2....3....43...7...11..157 - 3 = 411 - 7 = 415 - 11 = 4(the start of the nth term is 4n)4 x 1 = 4(but the first term is 3, so...)4 -1 = 3nth term = 4n - 1
The nth term is: 5-2n
The nth term in this sequence is 4n + 3.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
The sequence 2, 5, 8, 11 is an arithmetic sequence where the first term is 2 and the common difference is 3. The nth term can be expressed using the formula: ( a_n = 2 + (n - 1) \cdot 3 ). Simplifying this gives ( a_n = 3n - 1 ). Thus, the nth term is ( 3n - 1 ).
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
If you mean: 15 11 7 3 then the nth term is 19-4n