No.First off, 120 is not divisible by 9. (The sum of the digits of 120 is "3"; a number is divisible by nine if and only if the sum of its digits is divisible by nine.) For that matter, it's not divisible by 36 either; since 36 is itself divisible by 9, any number which is not divisible by 9 cannot be divisible by 36.The smallest number that's divisible by 1, 2, 3, 6, 9, 12 and 36 is "36" (it's also divisible by 4, which you left out).
36 12x3=36 9x4=36 and 108, which is 12x9
To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.
36
36 is the lcm
Add the digits of the number. If that total is divisible by nine, so is the original number. Example: 12,345,678 The digits total 36. 36 is divisible by 9. So is 12,345,678.
Add the digits of the number. If that total is divisible by nine, so is the original number. Example: 12,345,678 The digits total 36. 36 is divisible by 9. So is 12,345,678.
The number which is exactly divisible by 9 should have its digits adding to equal 9. Its 1st digit should be subtracted by 1 from its 9th factor. For example: 2 x 9 = 18, with 1 + 8 = 9 and 2 - 1 = 1 from 18.
Any number in the form 9k where k is the integers. Many numbers are divisible by 9, such as.. 9, 18, 27, 36, ....
27 for one then there's 36, 45, 54, 18 in short, any number divisible by 9 is also divisible by 3
36 = 1, 2, 3, 4, 6, 9, 12, 18 & 36 * * * * * Wrong. These are number that divide 36 not numbers that are divisible by 36! Numbers that are divisible by 36 are the numbers in the 36 times table: 36, 72 , 108, 144, 180 etc.
Any multiple of 9. In other words, any number of the form 9 * n. Add the digits of the number. If that total is divisible by nine, so is the original number. Example: 12,345,678. The digits total 36. 36 is divisible by 9. So is 12,345,678.