That's an infinite list, including 1.3
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
Let the first of the consecutive numbers be x. So the second number would be x + 2, and the third number would be x + 4. We have: 3x + 4(x + 1) + 5(x + 2) = 122 3x + 4x + 4 + 5x + 10 = 122 12x + 14 = 122 12x + 14 - 14 = 122 - 14 12x = 108 12x/12 = 108/12 x = 9 the first number x + 1 = 9 +1 = 10 the second number x + 2 = 9 + 2 = 11 the third numberCheck:(3*9)+(4*10)+(5*11) =? 122 122 = 122 True
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
Well, isn't that just a happy little question! To turn 122 into a mixed number, we divide 122 by the whole number it represents, which is 1. So, 122 as a mixed number is 122/1. Remember, there are no mistakes, just happy little accidents in math!
No, 122 is not a square number. A square number is an integer that can be expressed as the square of another integer. The square root of 122 is approximately 11.04, which is not an integer, indicating that 122 cannot be a perfect square.
41 should be in between 14 and 122
Let's see. 122 + 14 = 136. 136 + 14 = 150. 150 + 14 = ?
41.
The differences between the pairs of numbers up to that point are 31, 32, 33, 34. If the difference between the fifth number and the sixth number is equal to 35, that would make the next number equal to 122 + 243 = 265.
122! Your Welcome!
365.
122 - 26 = 9696 / 2 = 4826 + 48 = 74 = 122 - 48Answer: 7474
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
Let the first of the consecutive numbers be x. So the second number would be x + 2, and the third number would be x + 4. We have: 3x + 4(x + 1) + 5(x + 2) = 122 3x + 4x + 4 + 5x + 10 = 122 12x + 14 = 122 12x + 14 - 14 = 122 - 14 12x = 108 12x/12 = 108/12 x = 9 the first number x + 1 = 9 +1 = 10 the second number x + 2 = 9 + 2 = 11 the third numberCheck:(3*9)+(4*10)+(5*11) =? 122 122 = 122 True
2,5,14 - - 122 Difference between 5 & 2 = 3 = 3^(1) Difference between 14 & 5 = 9 = 3^(2) This leads one to suppose the next difference will be 3^(3) = 27 Hence 14 + 27 = 41 Similarly the next difference again will 3^(4) = 81 Hence 41 + 81 = 122 As required. So the sequence is 2,5,14,41,122. NB The next difference again is 3^(5) = 243 Hence 122 + 243 = 365 is the next term in the sequence. =
The next number works out as 365
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.