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Let the first of the consecutive numbers be x. So the second number would be x + 2, and the third number would be x + 4. We have: 3x + 4(x + 1) + 5(x + 2) = 122 3x + 4x + 4 + 5x + 10 = 122 12x + 14 = 122 12x + 14 - 14 = 122 - 14 12x = 108 12x/12 = 108/12 x = 9 the first number x + 1 = 9 +1 = 10 the second number x + 2 = 9 + 2 = 11 the third number

Check:

(3*9)+(4*10)+(5*11) =? 122 122 = 122 True

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15y ago

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