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What is the missing number in sequence 2 - 5 - 14 - - 122?
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
Find 3 consecutive natural numbers so that 3 times the 1st plus 4 times the 2nd plus 5 times the 3rd equals 122 what is the algebraic expression for that?
Let the first of the consecutive numbers be x. So the second number would be x + 2, and the third number would be x + 4. We have: 3x + 4(x + 1) + 5(x + 2) = 122 3x + 4x + 4 + 5x + 10 = 122 12x + 14 = 122 12x + 14 - 14 = 122 - 14 12x = 108 12x/12 = 108/12 x = 9 the first number x + 1 = 9 +1 = 10 the second number x + 2 = 9 + 2 = 11 the third numberCheck:(3*9)+(4*10)+(5*11) =? 122 122 = 122 True
What number is missing out of 2- 5- 14-122?
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
What is the distance between 122 degrees 25 minutes and 122 degrees 26 minutes?
What is the distance between 122 degrees 25 minutes and 122 degrees 26 minutes?
What is 122.18 rounded to the nearest whole number?
It is 122.
2 5 14 122 what is the missing sequence number?
41 should be in between 14 and 122
What is the next Number in sequence 122 136 150?
Let's see. 122 + 14 = 136. 136 + 14 = 150. 150 + 14 = ?
Missing number 2 5 14 122?
41.
What comes comes next in the number series 2-5-14-41-122?
The differences between the pairs of numbers up to that point are 31, 32, 33, 34. If the difference between the fifth number and the sixth number is equal to 35, that would make the next number equal to 122 + 243 = 265.
What number is between 212 and 32?
122! Your Welcome!
What number is next in this series 2 5 14 41 122?
365.
What number is exactly halfway between 26 and 122?
122 - 26 = 9696 / 2 = 4826 + 48 = 74 = 122 - 48Answer: 7474
What is the missing number in sequence 2 - 5 - 14 - - 122?
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
Find 3 consecutive natural numbers so that 3 times the 1st plus 4 times the 2nd plus 5 times the 3rd equals 122 what is the algebraic expression for that?
Let the first of the consecutive numbers be x. So the second number would be x + 2, and the third number would be x + 4. We have: 3x + 4(x + 1) + 5(x + 2) = 122 3x + 4x + 4 + 5x + 10 = 122 12x + 14 = 122 12x + 14 - 14 = 122 - 14 12x = 108 12x/12 = 108/12 x = 9 the first number x + 1 = 9 +1 = 10 the second number x + 2 = 9 + 2 = 11 the third numberCheck:(3*9)+(4*10)+(5*11) =? 122 122 = 122 True
What number comes next. 2 5 14 41 122?
The next number works out as 365
Find the missing number 2 5 14 -- 122?
2,5,14 - - 122 Difference between 5 & 2 = 3 = 3^(1) Difference between 14 & 5 = 9 = 3^(2) This leads one to suppose the next difference will be 3^(3) = 27 Hence 14 + 27 = 41 Similarly the next difference again will 3^(4) = 81 Hence 41 + 81 = 122 As required. So the sequence is 2,5,14,41,122. NB The next difference again is 3^(5) = 243 Hence 122 + 243 = 365 is the next term in the sequence. =
What number is missing out of 2- 5- 14-122?
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
