Lets say that the number you are looking for is equal to (X + 1)
X is one less than the number that answers your problem.
X must be divisible by 2, 3, 4, 5, and 6.
If something is divisible by 4, it is divisible by 2.
If something is divisible by 6 it is divisible by 2 and 3.
So, our number really only has to be divisible by 4, 5, and 6 and it will automatically by divisible by 2 and 3.
4 = 2 x 2
5 = 5
6 = 2 x 3
I've factored those 3 numbers to their prime factors.
X = 2 x 2 x 3 x 5.
The reason I didn't include three 2's in the line above is because the requirement that 6 has for being divisible by 2 is filled by both of the 2's that 4 requires to be there.
X = 4 x 15
X = 60
Because the answer to your problem is (X + 1)...
60 + 1 = 61
So, 61 is your answer. When divided by 2, 3, 4, 5, and 6, it will leave a remainder of 1.
3,456 x 4 = 13,824 13,824 + 1 = 13,825 13,825 / 7 = 1,975 Answer: 13,825 remainder not reminder, by the way
601 is one such number.
721 is one such number.
169 is the smallest such number.
any number 1 more than a number in the 3 times table i.e 4, 7, 10, 13...
How about 7 as an example
3,456 x 4 = 13,824 13,824 + 1 = 13,825 13,825 / 7 = 1,975 Answer: 13,825 remainder not reminder, by the way
A number divided by 2 its reminder is 1, A number divided by 3 its reminder is 2, A number divided by 4 its reminder is 3, A number divided by 5 its reminder is 4, A number divided by 6 its reminder is 5, A number divided by 7 its reminder is 6, A number divided by 8 its reminder is 7, A number divided by 9 its reminder is 8, A number divided by 10 its reminder is 9 what is that number?
7
601 is one such number.
721 is one such number.
169 is the smallest such number.
419 Nachiket Joshi solution: LCM(7,6,5,4,3,2)=420 now subtract 1 frm answer ...............so the answer will be 419..... TRICK: Since the diff between the remainder and dividend is common(1 in this case ) u subtract 1 from the LCM
58
2.3333
any number 1 more than a number in the 3 times table i.e 4, 7, 10, 13...
The numbers divided by 5 gives 1 remainder means it should end either 1 or 6. But in case of number ends with 6 will be divided by 2. So only number ending with 1 have to consider. Also the number should be divisble by 7. So when number ending with 3 is multiplied by 7 will give result of number ending 1. So, possibilities are 7*3, 7*13, 7*23, etc In that least number which solves this problem 7*43 = 301. So the least possible number is 301.