The first digit can be any one of 9 digits (anything but zero). For each of those ...
The second digit can be any one of 9 digits (anything but the previous one). For each of those ...
The third digit can be any one of 9 digits (anything but the previous one). For each of those ...
The fourth digit can be any one of 9 digits (anything but the previous one). For each of those ...
The fifth digit can be any one of 9 digits (anything but the previous one).
So the total number of possible arrangements is (9 x 9 x 9 x 9 x 9) = 59,049
out of a total of 99,999 different 5-digit numbers, or 59.05%.
89 x 90 = 8010 which are two consecutive two digit numbers that equal 8010.
24
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
1
21 and 20
89 x 90 = 8010 which are two consecutive two digit numbers that equal 8010.
Any 2 consecutive will always add up to an odd number and the number given is an even number
There is no one-digit number that is equal to both 14 and 28.
89
24
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
4
1
21 and 20
121
no
The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.