5
The answer depends on the number of choices available for each question.
In a multiple-choice test with 4 options (a, b, c, d) for each question, the probability of guessing correctly for each question is ( \frac{1}{4} ). If a student guesses on 10 questions, the expected number of correct guesses can be calculated by multiplying the number of questions by the probability of a correct guess: ( 10 \times \frac{1}{4} = 2.5 ). Therefore, the mean expected correct guesses for the student is 2.5.
25
In order to answer, the number of questions on the test must be given.
The fraction is(the number of multiple-choice questions) / (the total number of questions on the test)I can't be any more specific be cause you've neglected to mention either ofthose numbers in the question.
A multiple choice question comprises a question followed by a number - usually 4 or 5 - of which only one is correct and the others are not. The candidate has to select the correct one.
The probability will depend on how much you know and the extent of guessing.
If there are four possible answers to a question, then a guessed answer would have a probability of 1 in 4. If there are six questions, then the mean number of correct answers would be six times 1 in 4, or 1.5
If you have 5 questions, each with only two possible answers, the total number of combinations is 2*2*2*2*2 or 2^5 = 32. If the questions are all multiple choice and independent (ie no filters), then the total number of combinations must be the multiple of the numbers of choices for the questions.
you should be given a certain number of boxes and will either have to put a tick or cross in the box you think is the right answer.
The test's emphasis on simulations and increased number of multiple-choice questions from which there are random selections reduces the value of memorization and it is virtually impossible for candidates to anticipate specific questions
the correct way is to divide the number of questions you got right by the number of questions there are