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If you mean: y = 4x-2 and y = x+13 then x = 5 and y = 18
What is the solution set for the equations x-y=2 and -x+y=2
It is two terms of an algebraic expression.
The pair (2, 3) is the same as the pair (3, 2) but the ORDERED pair (2, 3) is NOT the same as the ORDERED pair (3, 2). In an ordered pair the order of the numbers does matter.
yx * yx = y2x.Using the law of exponents, we add the 2 exponents, getting you 2x rather than just 'x'.
x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)
When the order in which they are given makes no difference.
An ordered pair is a list of two numbers, in which the order matters. For example, (5, 2) is an ordered pair; this pair is not the same as (2, 5). For comparison, for the numbers in a set the order does not matter.
The ordered pair is (3, 2).
The ordered pair is (2, 3).
The ordered pair is (-1, -2).
On my TI-36X, it's 2 yx 1 0 = Thank you.