-log(3.5 X 10^-4 M)
= 3.4559
14 - 3.4559
= 10.5 pH
Molarity of hydrogen solution equals 2.3 X 10^-4 -log(2.3 X 10^-4) = 3.6 pH
Is always basic.
2
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
-log(9.40 X 10^-4) = 3 pH
9
-log(1.0 X 10^-4 M KOH) = 4 14 - 4 = 10 pH KOH ----------------
9
The pH of water increase.
concentrated solution of NaOH and KOH have the pH value about 13.
0.04 M KOH produces an OH- concentration of 0.04 M. Thus, the pOH is -log 0.04 = 1.4 and the pH will be 14 - 1.4 = 12.6
Yes, a concentrated solution of NaOH and KOH may have pH=14
You think probable to potassium chloride.
pOH = -log(10)[OH^-] pOH = -log(10) [ 48. x 10^-2] pOH = - (-1.31875...) pOH = 1.31875... pH = 14 - pOH pH = 14 - 1.31875... pH = 12.68124... pH = 12.68
[H3O+]= Kw/[OH-] = 1.00*10-14/6.70*10-2 =1.49*10-13 MpH= -log [H3O+] = -log (1.49*10-13)=12.8
...that solution is alkaline or basic.
The pH of a solution is defined as -log10[H+]. Thus a solution with a hydrogen ion concentration of 10-5M has a pH of 5. [H+] = 10-5 pH = -log[H+] pH = - log [10-5] pH = 5