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What is the percentage of oxygen to the nearest tenth in this compound Ba OH 2 8H2O?

The relative molecular weight of the compound nickel (II) sulphate heptahydrate NiSO4 7H2O is 280. 86. The total mass of oxygen in the compound is 176 g. Therefore the total percentage of oxygen to the nearest tenth is 60 percent


What is the percentage of oxygen to the nearest tenth in this compound Na½CO¾ x 10H½O?

72.70


What is the name of this compound NISO4 x 7 H2O?

The compound is called nickel sulfate heptahydrate.


A percentage 0.5688 to the nearest tenth?

0.57


How do you write 0.15 as a percent rounded to the nearest tenth?

0.2


What is the percentage of 150 rounded to the nearest tenth?

150.0


What is the percent of water to nearest tenth in this compound NiSO47H2O?

43.7


What is the percentage of water to the nearest tenth of niso4 and 7h2o?

44.9


What is 0.55047619 as a percentage and rounded to the nearest tenth?

0.6


What is 0.452 as a percent round to nearest tenth?

As a percentage 0.452 = 45.2%


What is the increase to the nearest of tenth of percentage of 5.75 to 7.50?

30.4% increase.


What is the percentage of water to the nearest tenth in this compound BaOH2 8H2O?

The compound Ba(OH)2·8H2O has 8 water molecules associated with it. To find the percentage of water in the compound, calculate the molar mass of the water molecules (8H2O) and the molar mass of the entire compound (Ba(OH)2·8H2O). Then divide the molar mass of the water by the molar mass of the entire compound and multiply by 100 to get the percentage of water.