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Q: What is the percentage strength of an ointment containing 300 mcg of drug y in a 10g tube?
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If there are 5g of zinc in 75g of ointment what is the percentage of the drug in the ointment?

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How many grams of zinc oxide should be to 3400g of a 10 percent zinc oxide ointment to prepare a product containing 15 percent of zinc oxide?

10% w/w = 10g/ 100g = x /3400g x = amount of drug in 3400 g or i would just say 10% of 3400 = 340 g of zinc oxide is needed to be 10% strength now how much do you have to add of zinc oxide to get 15% strength?? so you will end up with 340g of original PLUS x amount of new zinc oxide = the total drug you will use. so (340 + x) and to find percentage of drug over entire medication ... you would say (340 + x) over (3400 + x) and (3400 + x) = total medication with the additional zinc oxide you will want to add. finally: total drug/ total medication(Rx) = the new percentage strength sooo --> you wanted 15% to be the zinc oxide (drug) (340 + x) / (3400 + x) = 15% drug or better yet: (340 + x) / (3400 + x) = 15g/ 100g since 15% is 15 out of 100 so CROSS MULTIPLY and solve for x: (340 + x) * 100 = (3400 + x) * 15 34000 + 100 x = 51000 + 15 x--> 85 x = 17000 x = 200 so 200 grams of zinc oxide must be added to the original to get your 15% of drug strength.


When A medication with ratio strength of 1450 has percentage strength of what?

Unfortunately the colon from your ratio has been stripped form your question. There are two possibilities (if you had put spaces either side of your colon, it would have been obvious which):1 : 4501 part is the drug 450 parts are the non-active ingredients→ there are a total of 1 + 450 = 451 parts→ percentage of the drug is 1/(1 + 450) × 100% ≈ 0.22 %14 : 5014 parts are the drug 50 parts are the non-active ingredients→ there are 14 + 50 = 64 parts in total→ percentage of the drug is 1/(14 + 50) × 100% = 1 9/16 % = 1.5625 % ≈ 1.6 %


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