If it is a square, with side (s) length 2.5 units, then perimeter = 4*s = 10 units. Area = s2 = (2.5 units)2 = 6.25 square units.
A regular hexagon can be divided into 6 equilateral triangles. If a side equals S, then altitude equals S*sqrt(3)/2, and area of that triangle is (S2)*sqrt(3)/4. So the whole hexagon area is 6*(S2)*sqrt(3)/4 = 3*(S2)*sqrt(3)/2. Since S = perimeter/6, then you have: Area = Perimeter2*sqrt(3)/24.
It depends on what B is and what S is!
You want to know the dimension of a square if its perimeter and its area are numerically equal. If the side of the square is ' S ' ... Perimeter = 4 S Area = S2 Set Perimeter = Area: S2 = 4 S S2 - 4 S = 0 S ( S - 4 ) = 0 Two solutions: -- S = 0, -- S = 4 The solution (S = 0) is mathematically correct and completely useless. The real-world solution is: S = 4
It would depend on the shape that you are asking about. Also, only special shapes could express area as a function of the perimeter.Example: a square: area = s2, where s is the length of a side. Perimeter of a square is 4*s.So if P (for perimeter) = 4 * s, then s = P/4,and A (for area) = s2 = (P/4)2 = P2/16But for a rectangle that is not a square, there is no relationship between area and perimeter.
You only need to know the length of one side. Knowing the side length (s) you can find the area (multiply s by s) and perimeter (multiply s by 4)
The area of a square is equal to s2, where the side length is 1. We know the area is 1, so s2 = 1, and therefore s equals 1.We can now check the perimeter. The perimeter equals 4s. Plug in s = 1, and the perimeter is 4. So the square would have side lengths of 1.(Had the area an perimeter not matched up, the square would not have been possible.)
A square's area is side^2. The perimeter is side*4. I'll assume you meant 25 square yards. A=25 yd=s^2 s=5 yd P=5*4 yd=20 yd
A regular hexagon can be divided into 6 equilateral triangles. If a side equals S, then altitude equals S*sqrt(3)/2, and area of that triangle is (S2)*sqrt(3)/4. So the whole hexagon area is 6*(S2)*sqrt(3)/4 = 3*(S2)*sqrt(3)/2. Since S = perimeter/6, then you have: Area = Perimeter2*sqrt(3)/24.
The formula for the area of a square is: s * s where s = length of a side The formula for the perimeter of a square is: 4 * s where s = length of a side
The perimeter of a square is the sum of the lengths of its sides, while the area is the square of one of its sides. That is, if each side is S units long, then Perimeter = 4*S units and Area = S*S square units.
It depends on what B is and what S is!
Let s = semiperimeter (ie half the perimeter) So s = (a+b+c)/2 = (5 + 8 + 11)/2 = 24/2 = 12 Then area = sqrt[s*(s-a)*(s-b)*(s-c)] = sqrt[12*7*4*1] = sqrt[336] = 18.33 square units.
You want to know the dimension of a square if its perimeter and its area are numerically equal. If the side of the square is ' S ' ... Perimeter = 4 S Area = S2 Set Perimeter = Area: S2 = 4 S S2 - 4 S = 0 S ( S - 4 ) = 0 Two solutions: -- S = 0, -- S = 4 The solution (S = 0) is mathematically correct and completely useless. The real-world solution is: S = 4
Since a square has sides of equal length the area is the length of one side squared. You can find the length of one side by taking the square root of the area of the square. The length of one side is approximately 2.93. Then you plug in the length of the side into the perimeter formula. P = S+S+S+S P = 2.93+2.93+2.93+2.93 P = 11.72
p = s x 4p = s x 4p = s4100 = s4s =25cmarea = s x sarea = 25 x 25area = 625cm sq
Area of a square = s2 Perimeter of a square = 4s s = sqrt of the area = sqrt(3 inches2) Perimeter = 4sqrt(3 inches2) = 6.9282 inches
It would depend on the shape that you are asking about. Also, only special shapes could express area as a function of the perimeter.Example: a square: area = s2, where s is the length of a side. Perimeter of a square is 4*s.So if P (for perimeter) = 4 * s, then s = P/4,and A (for area) = s2 = (P/4)2 = P2/16But for a rectangle that is not a square, there is no relationship between area and perimeter.