I assume you're talking about a rectangle; if so, 44 feet.
The perimeter is found by multiplying the width by the length. So divide 50 by 12 and you get 4.166 width.
120 (10x12=120)
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
width=5 length=12
Area=length x width, A=lxw=10ft x 12ft=120ft2
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
Perimeter = 12+12+3+3 = 30m
12 meters
Perimeter= 2length x 2widthSince the perimeter is 40 and 2 times the width is 16, that means 2 times the length is 24. The length is 12.
Length + width = half of perimeter so width = p/2 - length ie (22-12) 10 yards.
A(rect) = w * l = 12ft*10ft = 120ft2Length * width = area10 * 12 = 120