Q: Find the length of a rectangle if the width is 8cm and the perimeter 40cm.?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

80 meters

26cm

(w = width)10 x w = 40(divide both sides by 10)1 x w = 4w = 4

One possibility is 15 x 5 (therefore perimeter is 15 x 15 x 5 x 5 = 40cm).

Assuming you meant area of 40 cm2, the rectangle would need to be 40 cm x 1 cm

Related questions

The width will be 30cm

First, you must find the width. Use Pythagoras' Theorem. Then, just add the lengths of the four sides, to get the perimeter.

80 meters

26cm

If a regular octagon has a perimeter of 40cm, then each side is 5 cm.

(w = width)10 x w = 40(divide both sides by 10)1 x w = 4w = 4

40cm

One possibility is 15 x 5 (therefore perimeter is 15 x 15 x 5 x 5 = 40cm).

The rectangle is 99 cm2 in area. Here's how we got it. The rectangle has length (l) and width (w). A length and a length and a width and a width all added up equals 40 cm. And l is 2 cm longer than w, so l = w + 2. If we add w + 2 and w + 2 (the two lengths) and w and w, we get 40 cm. That's 4w + 4 cm = 40 cm. 4w = 36 cm, and w = 9 cm. The width is 9 cm, and the length is 2 cm more or 11 cm. The rectangle is 9 cm by 11 cm, and its area is 9 x 11 cm2, or 99 cm2.

The perimeter is 40cm

The hollow block sizes in the Philippines are the following:40cm (length) X 20 cm (width) X 4 in (thickness)40cm (length) X 20 cm (width) X 5 in (thickness)40cm (length) X 20 cm (width) X 6 in (thickness

2*(40 + 8) = 2*48 = 96 cm.