12 inches
To find the perimeter of a rectangle, you use the formula: P = 2(length + width). For a rectangle that is 12 inches long and 10 inches wide, the calculation would be P = 2(12 + 10) = 2(22) = 44 inches. Therefore, the perimeter is 44 inches.
Assuming it is rectangle, then the perimeter equal twice the summation of length and width. Answer = 2 x (14 + 24) = 2 x 38 = 76 inches
P = 2(length) + 2(width) P = 2(12 inches) + 2(10 inches) P = 44 inches
Perimeter = 2*(Length + Width) = 2*(16 + 12) = 2*28 = 56 inches
Perimeter = width*2 + length *2 112 = 14 * 2 + length * 2 56 = 14 + length length = 56 - 14= 42
Length + width = half perimeter = 100". Length is 98", width is 2"
To find the perimeter of a rectangle, you use the formula ( P = 2 \times (width + height) ). For a rectangle that is 2 inches wide and 5 inches tall, the perimeter would be ( P = 2 \times (2 + 5) = 2 \times 7 = 14 ) inches. Therefore, the perimeter is 14 inches.
10 inches
20
You need the length...
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches