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What is the perimeter of a rectangle 11m long and 4m wide?
The perimeter of a rectangle is calculated using the formula ( P = 2 \times (length + width) ). For a rectangle that is 11 meters long and 4 meters wide, the perimeter is ( P = 2 \times (11m + 4m) = 2 \times 15m = 30m ). Therefore, the perimeter of the rectangle is 30 meters.
What is the area and perimeter to 22 meters long and 14 meters wide?
The area of a rectangle is calculated by multiplying its length by its width. For a rectangle that is 22 meters long and 14 meters wide, the area is 22 × 14 = 308 square meters. The perimeter is calculated by adding twice the length and twice the width, so the perimeter is 2(22 + 14) = 72 meters.
What is the perimeter of a carpet which is 7 meter long and 4 meters wide?
Perimeter = 2*(L + W) = 2*(7 + 4) = 2*11 = 22 metres.
How many meters of fencing do you need to enclose a garden if the yard is twenty six meters long and half as wide?
78 meters fencing goes around the yard so you are looking for the perimeter Perimeter=2length+2width Perimeter=2*26+2*13=52+26=78meters
What is 5 meters by 7 meters what is the perimeter of the room?
To calculate the perimeter of a rectangle, you can use the formula: Perimeter = 2(length + width). For a room measuring 5 meters by 7 meters, the perimeter would be 2(5 + 7) = 2(12) = 24 meters. Therefore, the perimeter of the room is 24 meters.
What is the perimeter if a rectangle which is 11 meters long and 4 meters wide?
Perimeter = 2*(L+ W) = 2*(11 + 4) = 2*15 = 30 metres.
What is the perimeter of a rectangle 11m long and 4m wide?
The perimeter of a rectangle is calculated using the formula ( P = 2 \times (length + width) ). For a rectangle that is 11 meters long and 4 meters wide, the perimeter is ( P = 2 \times (11m + 4m) = 2 \times 15m = 30m ). Therefore, the perimeter of the rectangle is 30 meters.
What is the area and perimeter to 22 meters long and 14 meters wide?
The area of a rectangle is calculated by multiplying its length by its width. For a rectangle that is 22 meters long and 14 meters wide, the area is 22 × 14 = 308 square meters. The perimeter is calculated by adding twice the length and twice the width, so the perimeter is 2(22 + 14) = 72 meters.
What is the perimeter of a lot if the lot is 15 meters long and 10 meters wide?
2*(15 + 10) = 2*25 = 50 metres
What is the perimeter of a rectangle that is 1.6 meters long and 0.8 meters wide?
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
What is the perimeter of a carpet which is 7 meter long and 4 meters wide?
Perimeter = 2*(L + W) = 2*(7 + 4) = 2*11 = 22 metres.
How many meters of fencing do you need to enclose a garden if the yard is twenty six meters long and half as wide?
78 meters fencing goes around the yard so you are looking for the perimeter Perimeter=2length+2width Perimeter=2*26+2*13=52+26=78meters
Calculate the perimiter of a rectangle which is eleven meters long by four meters wide?
perimeter = 2 * (length + width)= 2 * (11 + 4)= 2 * 15= 30 metresbasically 30 meters
What is 5 meters by 7 meters what is the perimeter of the room?
To calculate the perimeter of a rectangle, you can use the formula: Perimeter = 2(length + width). For a room measuring 5 meters by 7 meters, the perimeter would be 2(5 + 7) = 2(12) = 24 meters. Therefore, the perimeter of the room is 24 meters.
What is the perimeter of the penalty box?
The perimeter of the penalty box in soccer is calculated by adding the lengths of all four sides. The penalty box measures 16.5 meters (18 yards) from the goal line to the front and 40.3 meters (44 yards) wide. Therefore, the perimeter is calculated as: ( 2 \times (16.5 + 40.3) = 2 \times 56.8 = 113.6 ) meters. Thus, the perimeter of the penalty box is 113.6 meters.
What is the perimeter of 2 meters?
X Meters
What is the perimeter of an oblong buikding that is 45 m wide and 55m long?
To find the perimeter of an oblong building, you can use the formula for the perimeter of a rectangle, which is P = 2(length + width). For a building that is 45 m wide and 55 m long, the perimeter would be P = 2(55 m + 45 m) = 2(100 m) = 200 m. Therefore, the perimeter of the building is 200 meters.
