8 ft.
The area of a lot is not enough information to determine its perimeter. The most compact perimeter is approx 740 feet, which is attained by a circular lot. Consider the following rectangular plots, each is of area 1 acre: 100 ft * 435.6ft : perimeter = 1071.2 ft 10 ft * 4356 ft : perimeter = 8732 ft 1 ft * 4356 ft : perimeter = 87122 ft 0.1 ft * 43560 ft : perimeter = 871200.2 ft ... 0.000001 ft * 43,560,000,000 ft : perimeter = 87,120,000,000 ft (approx) = 16,500,000 miles. There is virtually no limit to how much the first dimension can be reduced and the perimeter increased.
There's a lower limit, but there's no upper limit.The smallest perimeter that a 96-ft2 rectangle can have is a square with 9.798-ft sides,for a perimeter of 39.192 ft. (rounded)But the perimeter can be as big as you want to make it, with no limit.Each of the following rectangles has area of 96 ft2 :1-ft x 96-ft . . . perimeter = 194 ft6-in x 192-ft . . . perimeter = 385 ft (0.073 mile)1-in x 1,152-ft . . . perimeter = 2,3041/6 ft. (0.436 mile)0.001-ft x 96,000-ft . . . perimeter = 192,000.002 ft. (36.36 miles)0.000001-ft x 96,000,000-ft . . . perimeter = 192,000,000.000002 ft ( 36,363.6 miles)
Any number greater than or equal to 8348.4 feet. A square of sides 2087.1 feet will have an area of 100 acres. A rectangle of any larger length (and corresponding shorter width) can have the same area but with a larger perimeter. eg 3000 ft * 1492 ft : perimeter = 8904 ft 4000 ft * 1089 ft : perimeter = 10178 ft 10000 ft * 435.6 ft : perimeter = 20871.2 ft 1 billion ft * 0.052 inches : perimeter = 2 billion ft (approx) 1 trillion ft * 0.000052 inches : perimeter = 2 trillion ft (approx) There is no end.
That depends on what you mean by a "20 ft semicircle".A semi-circle is a half circle.A 20 ft circle could be:A circle of diameter 20 ftThe perimeter of the semicircle is half the circumference plus the diameter → perimeter = 1/2π 20 ft + 20 ft= 10π + 20 ft≈ 51.42 ftA circle of radius 20 ftThe perimeter of the semicircle is half the circumference plus double the radius → perimeter = 1/2 2π 20 ft + 2 x 20 ft= 20π + 40 ft≈ 102.08 ftA circle of circumference 20 ftThe perimeter of the semicircle is half the circumference plus the diameter → perimeter = 1/2 20 ft + 20 ft ÷ π= 10 ft + 20/π ft≈ 16.37 ftHowever, if a 20 ft circle is a circle with a circumference (= perimeter) of 20 ft then a 20 ft semi-circle could be a semicircle with a perimeter of 20 ft→ perimeter = 20 ft
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.
The area doesn't tell you the shape or the perimeter. Even if you restrict it torectangles, there are an infinite number of those, all with different perimeters,that all have 42 ft squared of area.Here are a few of them. ALL of the areas are 42 ft squared.42 ft by 1 ft (perimeter = 86 ft)21 ft by 2 ft (perimeter = 46 ft)14 ft by 3 ft (perimeter = 34 ft)12 ft by 3ft6in (perimeter = 31 ft)7 ft by 6 ft (perimeter = 26 ft)If you're trying to make a square out of it, then the length of each side of the squareis sqrt(42), and the perimeter is 25.92 to the nearest hundredth.On the other hand, it could be a circle, and the perimeter (circumference) of the circleis 22.97 to the nearest hundredth.
Half an acre = 21780 sq feet.This could have a perimeter of any length greater than (or equal to) 523.16 feet.If the area is in the form of a circle of radius 83.26 feet, it will have the minimum perimeter of 523.16 feet.Or, you can have a square of 147.6 ft giving a perimeter of 590.3 ft,or a rectangle of 150 ft * 145.2 ft - perimeter = 590.4 ftor a rectangle of 100 ft * 217.8 ft - perimeter = 635.6 ftor a rectangle of 10 ft * 2178 ft - perimeter = 4376 ftor a rectangle of 1 ft * 21780 ft - perimeter of = 43562 ftetc, with the perimeter increasing without limit.Or, the area could be circular giving the minim590 feet.
An acre is 43560 square feet so any value greater than 740 feet. That perimeter is attained by a circle. But the outside measurement depends on how thin and long the area is: For example, a 100 ft wide x 435.6 ft plot would have a perimeter of 1071.2 ft a 10 ft wide x 4356 ft plot would have a perimeter of 8732 ft a 1 ft wide x 43560 ft plot would have a perimeter of 87122 ft a 0.1 ft wide x 435600 ft plot would have a perimeter of 871200.2 ft There is virtually no limit to how thin and long the plot can be and so no limit to how large the perimeter can be.
If the area of a square is one square foot, it means that each side of the square is one foot long. The perimeter of a square is the sum of all its four sides, so in this case, the perimeter would be 4 feet (1 foot + 1 foot + 1 foot + 1 foot).
It could take near enough forever. A million acres is 43560000000 sq ft. The minimum perimeter for an area of this size is 4*sqrt(43560000000) ft = 4*208710 ft = 834841 ft = 158 miles. But there is no maximum length for the perimeter. The million acres could be 43560 * 1000000 sq ft with a perimeter of 2087120 ft = 395 miles or 4356 *10000000 sq ft with a perimeter of 20008712 ft = 3790 miles or 435.6 * 108 sq ft with a perimeter of 2*108 ft = 37879 miles etc.
1 ft * 24 ft 1.1 ft * 23.9 ft 1.2 ft * 23.8 ft 1.3 ft * 23.7 ft 12.4 ft * 12.6 ft In fact if 0 < B < 12.5 ft and L = 25 - L ft then any rectangle with breadth B and length L will have a 50 ft perimeter.